   Chapter 5.4, Problem 31E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Evaluating a Definite Integral In Exercises 17-38, evaluate the definite integral. See Examples 3 and 4. ∫ 0 4 1 2 x + 1 d x

To determine

To calculate: The value of definite integral 0412x+1dx.

Explanation

Given Information:

The integral is 0412x+1dx.

Formula used:

The fundamental theorem of calculus states that,

If f is integrable on interval [a,b] then abf(x)dx=F(b)F(a).

The integration formula is xndx=xn+1n+1+C.

Calculation:

Consider the integral,

0412x+1dx

The integral in the radical form can be written as,

0412x+1dx=04(2x+1)1/2dx

Multiply and divide by 2,

04(2x+1)1/2dx=04(2x+1)1/2(2)dx2

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