A constant torque of 24.5 N. m is applied to a grindstone whose moment of inertia is 0.130 kg · m. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the angular equivalent of Wnet = FAx =. mv? -mv? is wnet = TA0 = lo} - lw?. You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.) rev/s
A constant torque of 24.5 N. m is applied to a grindstone whose moment of inertia is 0.130 kg · m. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the angular equivalent of Wnet = FAx =. mv? -mv? is wnet = TA0 = lo} - lw?. You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.) rev/s
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Energy Of A System
Section: Chapter Questions
Problem 15P: A small particle of mass m is pulled to the top of a friction less half-cylinder (of radius R) by a...
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A constant torque of 24.5 N · m is applied to a grindstone whose moment of inertia is 0.130 kg · m2. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the angular equivalent of
Wnet = FΔx =
mvf2 −
mvi2
1 |
2 |
1 |
2 |
is
Wnet = τΔ? =
Iωf2 −
Iωi2.
1 |
2 |
1 |
2 |
You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)
rev/s
![A constant torque of 24.5 N • m is applied to a grindstone whose moment of inertia is 0.130 kg · m². Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the
= FAx = mv? -mv,? is W,
2
angular equivalent of W,
= tA0 =
2
You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)
net
net
2
2
2
rev/s
еВook](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4b5e6981-f401-472f-b08d-28e5e6918f52%2Faa97c7aa-72d5-4b46-a521-5379efaa8b94%2Fbk3zb5c_processed.png&w=3840&q=75)
Transcribed Image Text:A constant torque of 24.5 N • m is applied to a grindstone whose moment of inertia is 0.130 kg · m². Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 14.0 revolutions. Hint: the
= FAx = mv? -mv,? is W,
2
angular equivalent of W,
= tA0 =
2
You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)
net
net
2
2
2
rev/s
еВook
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