   # A compound has the empirical formula CHCl. A 256-mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous compound. Give the molecular formula. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 8, Problem 78E
Textbook Problem
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## A compound has the empirical formula CHCl. A 256-mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous compound. Give the molecular formula.

Interpretation Introduction

Interpretation: The compound having empirical formula of CHCl should be identified if the 256 mL flask contains 0.800 g of this gaseous compound at 373 K and 750 torr.

Concept introduction:

Empirical formula of a compound is the smallest integer ratio of numbers of each element presented in that compound.

Molecular formula of a compound is integer multiple of empirical formula, the integer is depend upon the mass of empirical formula and the molecular mass of the compound.

According to ideal gas equation,

Molecularmass=Mass*R*TemperatureVolume*pressure

### Explanation of Solution

Explanation

The given data’s of the gas are,

• - mass = 0.800g
• - Temperature = 373 K
• - Pressure = 750 torr =750torr*1 atm760torr = .9868 atm
• - Volume = 256 mL = 0.256 L
• - Universal gas constant ‘R’ = 0.08206 L atm

According to ideal gas equation for molecular mass,

Molecularmass=Mass*R*TemperatureVolume*pressure

Therefore, the molecular mass of given diatomic gas is,

Molecularmassof given compound=0.800g*0.08206Latm/Kmol*373K0.256L*0

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