Chapter 9, Problem 65P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# The Deformation of Solids65. A 200.-kg load is hung on a wire of length 4.00 m, cross-section area 0.200 × 10−4 m2, and Young’s modulus 8.00 × 1010 N/m2. What is its increase in length?

To determine
The increase in length of a wire.

Explanation
Yongâ€™s modulus is defined as Y=stress/strain=(F/A)/(Î”L/L0) and from which, the increase in length of that wire is calculated as Î”L=(FL0)/(AY) .

Given info: The cross-sectional area of the wire is 0.200Ã—10âˆ’4â€‰m2 , Youngâ€™s modulus of the wire is 8.00Ã—1010â€‰N/m2 , length of the wire is 4.00â€‰m , mass of the load is 200â€‰kg , and acceleration due to gravity is 9.80â€‰m/s2 .

The formula for the increase in length of the wire is,

Î”L=(mg)L0AY

• m is mass of the load.
• g is acceleration due to gravity.
• L0 is length of the wire.
• A is cross-sectional area of the wire.
• Y is Youngâ€™s modulus of the wire.

Substitute 200â€‰kg for m , 9

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started