   Chapter 9, Problem 82AP

Chapter
Section
Textbook Problem

Superman attempts to drink water through a very  long vertical straw as in Figure P9.82. With his great strength, he achieves maximum possible suction. The walls of the straw don’t collapse. (a) Find the maximum height through which he can lift the water. (b) Still thirsty, the Man of Steel repeats his attempt on the Moon, which has no atmosphere. Find the difference between the water levels inside and outside the straw. Figure P9.8283. The human brain and spinal cord are immersed in the cerebrospinal fluid. The fluid is normally continuous between the cranial and spinal cavities and exerts a pressure

(a)

To determine
The maximum height through which superman can lift the water.

Explanation
Imagine that the superman can make the vacuum inside the straw and the pressure on the surface of water and all its surrounding of the straw is equal to atmospheric pressure. So due to this pressure difference, the water would be pumped into the straw to a maximum height and suppose superman has such a height of straw, he definitely drinks enough water. So the height would of the straw would be P=P0+ρgh0=Patm+ρwghmaxhmax=Patm/ρwg .

Given info: The density of water is 1.00×103kg/m3 , acceleration due to gravity is 9.80m/s2 , and atmospheric pressure is 1.013×105Pa .

The formula for the maximum height of the straw is,

hmax=Patmρwg

• Patm is atmospheric pressure.
• ρw is density of water

(b)

To determine
The difference between the water levels inside and outside the straw.

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