preview

Designing And Performing A Procedure

Decent Essays

Title: Designing and Performing a Procedure Used to Determine the Percent of Water in a Hydrate

Objective: To determine the chemical formula for the “Mystery Hydrate”
Problem: Determining the formula for the “Mystery Hydrate”
Variables:
Independent Variable (IV)
What percent water is the Mystery Hydrate

Dependent Variable (DV)
The amount of hydrate left after heating

Introduction

“Hydrates are substances that include water in their formula. The water is not actually part of the chemical substance and this is reflected in the way the formula is written” (ChemTeam, 2016). An example of a hydrate is beryllium sulfate tetrahydrate, which is written like: BeSO4· 4H2O. All hydrates follow the same formula format; with the …show more content…

at and weigh
Pour hydrate crystals into crucible
Set up ring stand with clay triangle
Adjust height of ring to be 10 cm above a Bunsen burner
Place crucible on clay triangle with crucible tongs and set lid ajar
Place Bunsen burner on bench and light with igniter
Move Bunsen burner under crucible on ring stand and adjust flame to “kiss” crucible
Heat for 10 minutes
Turn off flame
Remove crucible from ring stand and place on wire mesh to cool for 5 minutes
Move crucible with tongs to the balance and weigh
Place crucible back on ring stand with lid closed
Ignite Bunsen burner and heat for 7 minutes
Repeat steps 11 - 15 until the difference in masses is 0.01g

Data

Item
Mass (g)
Crucible & Lid
16.96g
Mystery Hydrate Crystals
4.40g
Crucible & Lid & Mystery Hydrate Crystals after 1st Heating
19.17g
Crucible & Lid & Mystery Hydrate Crystals after 2nd Heating
19.17g

Interprets and analyzes data

Calculations

Molar Mass MgSO4
Atomic mass of Mg + Atomic mass of S + Atomic mass of O * 4 = Molar mass of MgSO4

24.31u + 32.07u + 64.00u = 120.38u

MgSO4 · 5H2O
Molar mass of MgSO4 + Atomic mass of H * 10 + Atomic mass of O * 5 = Molar mass of MgSO4 · 5H2O

120.38u + 10.10u + 80.00u = 210.48u

MgSO4 · 7H2O Molar mass of MgSO4 + Atomic mass of H * 14 + Atomic mass of O * 7 = Molar mass of MgSO4 · 7H2O

120.38u + 14.14u + 112.00u = 246.52u MgSO4 · 10H2O Molar mass of MgSO4 + Atomic mass of H * 20 + Atomic mass of O * 10 = Molar

Get Access