Finding The Steady State Temperature Distribution Of A Beam

The goal of the beam project is to design and construct a beam that can hold a given amount of weight without breaking. The beam is required to hold a concentrated load of 375 lbf on the X-axis and 150 lbf on the Y-axis. The maximum allowable weight of the beam is 250 grams. The maximum allowable deflection for the beam is 0.230 in. and 0.200 in. for the X and Y-axis respectively. The beam is required to be 24 in. in length, and it will be tested on a simply supported configuration spanning 21 in. All calculations are to be done under the assumption that the density of basswood is 28 lbm/ft3 and the modulus of elasticity for basswood is 1.46x106 lbm/in2. Given the constraints of a spending cost of $10.50, a maximum beam weight of 250 grams,

Thermodynamics is “the study of the effects of work, heat, and energy on a system”. In Thermodynamics to find the temperature change I will use the formula: Q=MCT. In this formula Q represents the heat added, M is the mass, C is the specific heat, and Tis the change in temperature. From using this equation I will later figure out the uncertainties I have in this experiment using the formula: Amount of DataGiven (average data/ amount of data given) then you take the given and subtract it from the answer from the formula above, lastly you add it up and square root it. Next, you put it in this form: average data ± answer using the formula above. Lastly, I will use error bars on the graphs to represent the uncertainty of the graphs. Error bars are represented by this image:

14. Calculate the change in the metal’s temperature by subtracting the initial temperature of the iron from the final

6. Restate your predictions that were correct and give the data from your experiment that supports them. Restate your predictions

in the xy-plane is equal to the radius (R) of the beam pipe, as shown in Fig.~\ref{beampipeconversion},

I notice that angle H is in the opposite of the right angle and therefore angle H has a value of 90 degrees. This will mean that the sum of the angles that are listed as (8m - 18) and (5p + 2) will add up to 90. And since the angle (7m + 3) is opposite to the (5p + 2) angle, they're equal. Therefore (8m - 18) + (7m +3) = 90.

Firstly, connect WL 110.04 to GUNT Heat Exchanger Service Unit WL 110 with correct piping. For this experiment, jacket water with batch mode is selected for heating. Later, start GUNT WL 110 software with a computer and set up data logging with the correct mode of operation and parameters. Temperature of hot water supplied is set to 70 °C with TI C7 controller. Next, switch on the heater and pump for hot water to flow through the jacket. Hot water flow rate is set to 1.6 l min-1 by adjusting valve V1. Then, weigh and record approximately

4th grade students will be provided with shapes that they can trace on their illustrations.

The data shown in Table 01 illustrates the temperature difference measured by the LM35 sensor at different distances from the heat source. A decreasing trend is very prominent through this data. Because of this, it can be concluded that the farther the distance from the heat source the temperature sensor is, the less accurate the reading. This conclusion can also be seen through Table 02, which represents the time difference of the temperature rise and fall times for the sensor, both normally and through active convective

My hypothesis of if I measure the circumference and diameter of circular objects than the relationship of the graph should be a linear line. My hypothesis was correct because my line fit best with the linear line. The percent error of the experiment was 3.141%. A possible error could be not getting the exact number to the hundredths place. One way to change that is to get a measuring tape that has all of the numbers so that you can get an exact number to the hundredths place. From this experiment I learned that your numbers have to be exact or your percent error won’t be what you want it to be. One way to fix these error is to have the whole class measure the same objects so that you can compare your results with their results and get the exact number. To improve this

The results were taken and the specific heat capacity of the 100g brass mass were calculated. For the results to be accurate we did 5 trials and finally we had our averages which were 21, 2°C, 95, 6°C, 25, 4°C

Madi King & Beth Braswell December 16, 2015 ICE CREAM THERMODYNAMICS LAB Introduction- The purpose of this lab was to determine how to lower the freezing point of water in order to freeze an ice cream mixture. In ice cream making removing 1000 calories of heat from a milk/sugar mixture is removed and is then transferred to the salt/ice mixture. Energy is conserved and this meets the requirements for the first law. Heat is always moving from the hotter object to the cooler one.

Heat transfer processes are prominent in engineering due to several applications in industry and environment. Heat transfer is central to the performance of propulsion systems, design of conventional space and water heating systems, cooling of electronic equipment, and many manufacturing processes (Campos 3).

The beam was loaded the mid-length in 2.745 lbs. increments up to 6.745 lbs. The change in clearance of every load step was measured and data was recorded.

the beaker filled with water. I will also do this twice one in a small