Haybalor
Imagine you have five bales of hay. For some reason, instead of being weighed individually, they were weighed in all possible combinations of 2: bales 1 and 2,bales 1 and 3, bales 1 and 4, bales 1,and 5, bales 2 and 3, bales 2 and 4, and so on.
The weight of each combination was written down without keeping track of weight marched witch pairs of bales. The weights in kilograms were 80, 82, 83, 84, 85, 86, 87, 88, 90, and 91.
The first thing I did when trying to find this answer is that I tried to do guess and check. At the start I started with forty because that was half of the first answer we needed. So I did 40 plus 40 because that's how I would get to 80, and so B would be 40. Then I did A+C, and 40 was A and that left C to be 41 because I had to get to 81. Then I went on to the next part where I had to do B+C. I already knew that B was 40, and C was 41, but I needed to get 80 but when you add B+C when A is forty then it's wrong. So then I tried to have A start out to be 41. I did A+B, and I was trying to get to 80 so B was 39. Then I did
A+C, and with A being 41 then C would have to be 38. Then I started to notice a pattern. The pattern was that every time A went up one then B,C,D, and E would all go down one. So then I did, B+C, which was
39+38 and that would only get me to 77 when I needed 80.
After weeks of working on the Hay Baler my teacher had put us in a big group because none of us had the answer right to the problem. He assigned each of us to number to start with to be A. My
number
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Then while we were thinking if we changed one thing then everything would be wrong and it could have been a long process if we didn't think the right numbers that we could
K 13. C 14. C 15. E 16. D 17.
The solution is 0.25(15) + 0.25(35). The order in which the products are added does not matter. This is an example of using the commutative property.
seven. Then I tried 21, but that didn’t fit either. I kept going up by multiples of seven trying to find
Since m = 7, I immediately know that (8m - 18) = 38, and (7m + 3) = 52.
It’s hard to keep all the math rules straight. You may have been thinking of addition. With addition we would
Bales A+C=82, A+D=83, A+E=86, B+C=84, B+D=85, B+E=88, C+D=87, C+E=91, D+E=91. That is just one way to do the problem. My proof that this is the correct answer is because the numbers for each letter added up, equals the weights as given in the book. There are 10 different ways to this problem. I only could figure out one of the ten different ways to do the problem.
Running with this information can now write out the equation AB2 + BC2 = AC2. One important thing is that we must note that AB is equal to “X” and the line segment of BC is equal to that of 2x+4, and that AC will be equal to that of 2x+6. So we will now input this information to create (x)2 + (2x + 4)2 = (2x + 6)2 and begin factoring each term into two sections. These two sections will be as x*x + (2x + 4)(2x + 4) = (2x + 6)(2x + 6). x times x is x2. An important tool to use now would be the FOIL method, so we will take (2x + 4)(2x + 4) and create 4x2 + 16x + 16. Right off the bat we notice that we have like terms. So we will add x2 to 4x2 to get 5x2. This will create 5x2 + 16x + 16 = 4x2 + 24x+ 36. Now we will use the subtraction property to get 5x2 – 4x2 + 16x – 24x + 16 – 36 = 0, however we still have like terms, so because 5x2 is a like term with -4x2 we will add them together to get x2. We will also combine 16x and –24x and also 16 and –36 which are also like terms and create –8x and –20, our equation should now look like x2 – 8x -- 20 = 0.We will now factor the equation from left to right, first factoring x2 which has 1 coefficient so the fact will be 1 and -1. The other term will be 20 which have no coefficient so we will do 5x4 and then 4 still can be divided so 2x2. This will create 20=225.
(60% are 30 s) + (15% are 40 s) + (5% are 240 s) + (3% are 50 s)
($372 + $135 + 500) / ($2.21 - ($0.83 + .40)) = 1,028 [+/- 31]
(Note: You can use tables or a financial calculator. If you use a calculator, please provide the inputs you used to solve the problems.) (5 points each = total 20 points)
To start the discussion, I wrote the following open sentence for Madison: 5 + 6 = ____. Madison quickly responded “11”. When I asked how she arrived at her answer, she indicated that this number fact was something that she had known since kindergarten.
Explain to Anna, Blake, and Christine who is correct, and identify any errors that you find. Provide the correct manner to fix those problems, and identify the correct answer. Use complete sentences.
____X___ 50. Jackie enjoys shopping for new clothes, surfing the internet, and walking her dog.
∏i = (Pe + 40 - 100) x 100 = 100 x Pe –6,000 -------------------- [1]