Hydrate Lab Report for Chemistry Lab

823 WordsNov 19, 20134 Pages
9-19-13 Dehydrating and Rehydrating a Hydrate Introduction The mass percent of water was determined using the mass of water and dividing it by the total mass of the hydrate and then multiplying that answer by 100%. The number of moles of water in a hydrate was determined by taking the mass of the water released and dividing it by the molar mass of water. The number of moles of water and the number of moles of the hydrate was used to calculate the ratio of moles of water to moles of the sample. This ratio was then used to write the new and balanced equation of the dehydration process. The sample was then rehydrated to the original state and the percent of the hydrate recovered was calculated by using the mass of the rehydrated sample by…show more content…
3. When the anhydrous sample was rehydrated, only 93.4% of the sample could be recovered. This was because some of the mass of the sample remained stuck to the filter paper and could not be measured in the final mass calculation. This automatically resulted in less mass and did not allow for 100% of the mass to be recovered. 4. If the hydrate would have been overheated and had released a gas, there would have been excess mass released because the mass of the gas that would have been released and water released combined would have been greater than the mass of just the water released. The way to know if that had happened would have been if the mass of the water released would be over 2. 5. I believe that with a Bunsen burner to dry would have provided more accurate results for the hydration number because the heat can be applied more directly and the time to heat would be faster, giving less room for error in the

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