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Molar Mass Of An Unknown Compound Using Freezing Point Depression

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Finding Molar Mass of an Unknown Compound using Freezing Point Depression
Farida Elassar*, Pranav Menon
Introduction: Certain species of animals and fish survive the cold by increasing the concentration of solutes in their blood to lower its freezing point. In this experiment, we will be measuring the freezing point depression of the aqueous solutions of an unknown compound to ascertain the unknown’s molar mass and therefore its identity.
Method: Firstly, the experimental apparatus was set up by clamping the Vernier temperature probe directly to a ring stand. For trial 1, the mass of a clean, dry 11-dram vial was recorded to the nearest 0.0001 gram before 15 mL of distilled water were added to the vial and it was weighed again. An ice bath …show more content…

The data points where supercooling occurred were omitted. I could recognize these data points as the temperature decreased before increasing and then stabilizing, creating a small dip in the graph. Anomalous data points were also omitted. For example, if the temperature suddenly increased during cooling because the probe was moved out of the solution due to stirring, that point was omitted. For each trial a cooling and freezing line were plotted. Trendlines were added and projected until they intersected, the point of intersection of the cooling and freezing trendlines indicates the freezing point of the distilled water or the aqueous solutions. The equation of the trendlines could be used to determine the freezing …show more content…

This is because salt is an electrolyte and sucrose is not. Freezing point depression is a colligative property, therefore the more solute particles in the solution the lower the freezing point. Electrolytes like sodium chloride dissociate when dissolved in water, therefore they always have a van’t Hoff factor larger than 1, while nonelectrolytes always have a van’t Hoff factor of 1. For example, sodium chloride has a van’t Hoff factor of 2, increasing the concentration of its particles in a solution by 2, making it twice as effective as sucrose in decreasing the freezing point of its solvent. As a result, less salt would keep roads unfrozen at lower temperatures than sucrose, making it the better choice. If the temperature is lower than the eutectic temperature of the salt solution, it is pointless to dispense salt as the solution will become saturated rapidly and the solvent will

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