Chapter 6. Uniform Acceleration
Problems:
Speed and Velocity
6-1. A car travels a distance of 86 km at an average speed of 8 m/s. How many hours were required for the trip?
[pic] [pic] t = 2.99 h
6-2. Sound travels at an average speed of 340 m/s. Lightning from a distant thundercloud is seen almost immediately. If the sound of thunder reaches the ear 3 s later, how far away is the storm?
[pic] t = 58.8 ms
6-3. A small rocket leaves its pad and travels a distance of 40 m vertically upward before returning to the earth five seconds after it was launched. What was the average velocity for the trip?
[pic] v = 16.0 m/s
6-4. A car travels along a U-shaped curve for a distance of 400 m in 30
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For Problem 6-17, what is the maximum displacement from the bottom and what is the velocity 4 s after leaving the bottom? (Maximum displacement occurs when vf = 0)
2as = vo2 - vf2; [pic]; s = +21.3 m vf = vo + at = 16 m/s = (-6 m/s2)(4 s); vf = - 8.00 m/s, down plane 6-19. A monorail train traveling at 80 km/h must be stopped in a distance of 40 m. What average acceleration is required and what is the stopping time? ( vo = 80 km/h = 22.2 m/s)
2as = vo2 - vf2; [pic]; a = -6.17 m/s2
[pic] ; t = 3.60 m/s
Gravity and Free-Falling Bodies
6-20. A ball is dropped from rest and falls for 5 s. What are its position and velocity? s = vot + ½at2; s = (0)(5 s) + ½(-9.8 m/s2)(5 s)2 ; s = -122.5 m vf = vo + at = 0 + (-9.8 m/s2)(5 s); v = -49.0 m/s
6-21. A rock is dropped from rest. When will its displacement be 18 m below the point of release? What is its velocity at that time? s = vot + ½at2; (-18 m) = (0)(t) + ½(-9.8 m/s2)t2 ; t = 1.92 s vf = vo + at = 0 + (-9.8 m/s2)(1.92 s); vf = -18.8 m/s
6-22. A woman drops a weight from the top of a bridge while a friend below measures the time to strike the water below. What is the height of the bridge if the time is 3 s? s = vot + ½at2 = (0) + ½(-9.8 m/s2)(3 s)2; s = -44.1 m
6-23. A brick is given an initial downward velocity of 6 m/s. What is its final velocity after falling a distance of 40 m?
2as = vo2 - vf2 ; [pic]; v = (28.6 m/s;
The parcel starts descending at 6000’ feet, the temperature at this height is 50.1 F, and is above the original LCL. The new LCL is at 6000’ feet as the parcel is starting its descent down the lee side of the mountain. The mixing ration to start to movement up the mountain was approx 18.9 g/kg and the descent capacity is approx 7.6 g/kg.
13. Mrs. Davis bought 6 pounds of grapes for $18. At this rate, how much would 72 ounces of grapes have
Problem: “Eight balls were in the basket. Some of the balls were removed from the basket. Now there are six balls. How many balls were removed from the
T= 40ms, I figured this by guessing cause I could not find any information on how to calculate. So I used the equation for t and plugged in different numbers until I got the 10ms that was already given in the table. t= T x 0/360= 40ms x 90/360= 0.01 x 10^-3= 10ms
15) A cart starts from rest and accelerates at 4.0 m/s2 for 5.0 s, then maintain that velocity for 10 s, and then decelerates at the rate of 2.0 m/s2 for 4.0 s. What is the final speed of the car?
33. Why is it that a cat that falls from the top of a 50-story building will hit a safety net below no faster than if it fell from the twentieth story?
* f times c = λ (where c is the speed of light: 3 x 108 meters / second)
If we measured in meters then a=4.9.) t is the time in seconds, v0 is the initial velocity of 30 feet per second, and s0 is the initial height or 4 feet. Thus we have:
block is moving with a speed of 6 meters per second. What is the magnitude of the unknown force?
4. A boat drifts down a 200-mile river at a rate of 6 miles per hour for
After doing this problem, I found that I am very comfortable using the kinematic equation of vf = vi+at, when I use this equation I find that I always get the right answer for the problem, which is great, and I have no further questions to help me understand this
2. Falling Times (in seconds) 3. Object 4. Horizontal Speed 5.
If the object was thrown upwards with an speed of 6 m/s. How long will it be in air, if you catch it when it returns?
Notice how it barely exceeds 0.5 m/s2 and averages only (0.14±0.03)m/s2 which is far from 1 m/s2.)