Essay on Seperation of a Mixture Lab Report

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The purpose of this lab is to find out how components of a mixture can be separated and analyzed.


The procedure for this lab report is as follows:
1. Mixture is taken, and has to be measured in order to meet the requirements of 2-3g.
2. The mass of the tray is measured and then the scale is zeroed out and the mixture is added to find out the mass of the original mixture.
3. Next, find the mass of the 250mL beaker, zero out the scale, pour the mixture in, and weigh to find the mass. Find the mass of the 100mL beaker as well.
4. In order to separate the iron from the mixture, take a bar magnet inside of a Ziploc bag, and swirl it through the mixture.
5. The iron will stick
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• During the filtration process, the salt seemed to not be dissolving as quickly as thought, and more water was needed.
• When the salt water was being boiled, all of the sudden the water turned into what looked like foam and the salt started popping.
• When the sand was taken out of the chemical oven, salt particles that had not been dissolved were found on the bottom of the filter paper.
• The iron had a high magnetism, while sand and salt had none at all.
• The salt had a high solubility in water while the sand did not.
• The physical appearance of the iron resembled rough tiny little black hairs.


The data for this lab is from data table B, as well as answers to post-lab questions 6 and 7.

Data Table B: Separation of a Mixture:

Mass of Original Mixture: 2.07g
Mass of Recovered Iron: .6g
Mass of Recovered Salt: .95g
Mass of Recovered Sand: .98g
Total Mass of Recovered Solids: 2.53g

Post-Lab Questions:

6. Mass percentage of salt: 44% Mass percentage of sand: 46% Mass percentage of iron: 17%

7. Percent yield for salt = 46% Percent yield for sand = 47% Percent yield for iron = 29%


Results: In this lab, the largest amount of recovered solids was the sand. The smallest amount of recovered solids was the iron. The total mass of recovered solids was

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