. A vertical cut is made through a homogeneous soil mass (c=20 kPa,ϕ=20°,γ=16.50 ?? ?3 ⁄ ). Estimate the safe depth of the cut, taking a factor of safety of 2 using Culmann’s method
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Q: Calculate the theoretical depth of penetration 32 kN/m 3.5 m Clay C = 12 kN/m2
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Q: Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a…
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Q: What is the critical depth of a vertical cut in a saturated cohesive soil withc=1.5 t/m2 andy = 16…
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1. A vertical cut is made through a homogeneous soil mass (c=20 kPa,ϕ=20°,γ=16.50 ?? ?3 ⁄ ). Estimate the
safe depth of the cut, taking a factor of safety of 2 using Culmann’s method
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- A vertical cut is made through a homogeneous soil mass (c=20kPa, φ=20deg, γ=16.5kN/m3). Using Culmann's method, determine the safe depth of the cut, taking a factor of safety of 2.0.A vertical cut is to be made in a purely cohesive clay deposit (c'=30kPa, φ'=0deg, γ=16kN/m3). Find the maximum height of the cut which can be temporarily supported. From the stability chart, the stability number can be used as 0.261.A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the maximum depth in meters up to which the cut could be made?
- A cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.A 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³ Determine the factor of safety. [Take area of wedge = 39 m²]
- For a railway track 7 m high embankment is required. The clay to be used for the embankment was found to have c = 20 kN/m2and unit weight = 19 kN/m3 Compute the critical maximum side slope angle for the embankment if a hard rocky stratum was found 3.5 m below the ground level. Assume ϕ for the clay equal to zero. The following values are given from Taylor's chart for depth factor D = 1.5 :Q9.1 - A 25-m high rock cut with a face angle of 60° has been excavated in a massive, very weak volcanic tuff. A tension crack has opened behind the crest and it is likely that the slope is on the point of failure, that is, the factor of safety is approx imately 1.0. The friction angle of the material is estimated to be 35°, its density is 25kN / (m ^ 3) and the position of the water table is shown on the sketch of the slope (Figure 4). The rock contains no continuous joints dipping out of the face, and the most likely type of failure mode is circular failure. Required- (a) Carry out a back analysis of the failure to determine the limiting value of the cohesion when the factor of safety is 1.0. (b) Using the strength parameters calculated in (a), determine the factor of safety for a completely drained slope. Would drainage of the slope be a feasible method of stabilization? (c) Using the ground water level shown in Figure 4 and the strength parameters calculated in (a), calculate the…Q.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
- (Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m3/s. The slope is 0.004 and is paved with smooth concrete (n = 0.012). a. What is the critical depth? b. What is the normal depth? c. Is it a mild slope, or steep?Hint: Compare critical depth with normal depth OR find the critical slope (??) and compare it with bed slope(?0) d. Is the depth increasing or decreasing upstream? Why would that be (e.g. a spillway, dam, etc.)?Hint: For the first part, use ????=?0−?1−??2 to show if the depth is decreasing/increasing (either by finding Fr and S, OR by simply using the values of ?, ?? and ?0 to figure out if the fraction is +/-). e. How would you conceptualize the flow – what regime (e.g., S1, S2, S3, M1, M2, M3 in Figure 10.20)? f. Determine the depth 3.3 m upstream from a section that has a measured depth of 1.69 m.Hint: If you are using MATLAB, solve the GVF differential equation (????=?0−?1−??2) and find flow depth y at location x = -3.3 m. If you are using…A rectangular channel 5.8 m wide by 1.4 m deep was laid to have a hydraulic slope of 0.001. Using n = 0.013. 1. What is its yield in cubic meter per second? 2. What savings in earth excavation could be realized by using most economical proportion? 3. What savings in lining per meter length could be realized by using most economical proportion?