. In this question you will adapt two different ways to compute ſsec® de in order compute ſcsc0 d0. Adapting a solution you've seen to solve a new problem is an important skill in mathematics; it means that instead of just solving one problem, you can solve many different problems! (1) See p. 483 of the textbook for the most common strategy for integrating sece. Adapt this to compute Scsc0 d0.
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In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.
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Pls Help!
![Isaac Barrow (1630–1677) in his Geometrical Lectures (Lect. XII, App. I) gave the first
"intelligible" proof of the result, but it was couched in the geometric idiom of the day. It is
especially noteworthy in that it is the earliest use of partial fractions in integration. Thus we
reproduce it here in modern garb:
1
de
cos e
O do =
cos e
de
-) Cos? 0
cos 0
de
=J1- sin?0
cos e
do
-J (1- sin0)(1+ sin 0)
cos e
1- sin0
cos 0
1+sine
+
do
-In|1-sine|+In|1+sin |]+ c
=
1+ sin0
-n1-sine
1+ sin0 1+sin0
In
1-sin0 1+sin 0
+c
|(1+sin0)²
-n1-sin*o
-In
+c
|(1+sin0)?
In
+c
=
(cos8)?
1+sin0
+ c
= In cose
=In|sec0+ tan 0|+c.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fde24d8a6-50dc-4080-850d-249835a4e10e%2Ffe6cdb3e-07c4-43ac-8099-764e33d75497%2F6tr2316_processed.png&w=3840&q=75)
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