. The freezing point depression of a solution of glucose (C,H,206, molar mass = 180.0 g/mol) is -10.3°C. Calculate for the molarity of the glucose solution given that the density of the solution is 1.50 g/mL and the freezing point constant, K¢, of water is 1.86 °C kg mol·1.

An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
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Chapter13: Chemical Reactions
Section: Chapter Questions
Problem 38SA: Suppose you are given the volume (in liters) of a salt (NaCl) solution and its molarity. Explain how...
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1. The freezing point depression of a solution of glucose
(C,H1206, molar mass
Calculate for the molarity of the glucose solution
given that the density of the solution is 1.50 g/mL and
the freezing point constant, K¢, of water is 1.86 °C kg
mol·1.
= 180.0 g/mol) is -10.3°C.
%3D
Transcribed Image Text:1. The freezing point depression of a solution of glucose (C,H1206, molar mass Calculate for the molarity of the glucose solution given that the density of the solution is 1.50 g/mL and the freezing point constant, K¢, of water is 1.86 °C kg mol·1. = 180.0 g/mol) is -10.3°C. %3D
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