please do this typewritten so I will upvote and skip this if you already did this. the big number on the right is only for numbering. please do not mind that. thank you 97. A 4.052 g sample of HCl, sp.gr.1.18 required 44.15mL of 0.9035N NaOH in a titration. Calculate the sodiumcarbonate (106g/mol) titer of the sample.97

Given as, Mass of HCl = 4052 mg = 4.052 g Specific gravity of HCl = 1.18 Volume of NaOH = 44.15 mL…

Answered: .18 required 44.15 sample.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.21QAP

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please do this typewritten so I will upvote and skip this if you already did this. the big number on the right is only for numbering. please do not mind that. thank you

97. A 4.052 g sample of HCl, sp.gr.1.18 required 44.15mL of 0.9035N NaOH in a titration. Calculate the sodium
carbonate (106g/mol) titer of the sample.
97

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