I need help with these questions Name:.5ksProblem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 secondsfor the ball to make one revolution.A.S What is the centripetal acceleration of the ball?0.5.Trev2rpmC60minac=(.5)?/2 rom=.25/2rpm- 125m/;2B. If the ball is being kept in a circular path by the string, then what is the tensionin the string?strins2m.125 mls= ,0 0125m

Given: Mass of ball, m==50 gram = 0.050 kg Radius of circle= length of string, R=2 m Time taken to…

.5ks Froblem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 seconds for the ball to make one revolution. Irev 0.5. 2rpm A.4 EWhat is the centripetal acceleration of the ball? 60 min ac=(.5)?/2 rgm 2 rpm -3 -. 25/2rpm B. If the ball is being kept in a circular path by the string, then what is the tension in the string? - 5

.5ks Froblem 3: A 50 gram ball tied to a 2 meter string is being swung in a circle. It takes 0.5 seconds for the ball to make one revolution. Irev 0.5. 2rpm A.4 EWhat is the centripetal acceleration of the ball? 60 min ac=(.5)?/2 rgm 2 rpm -3 -. 25/2rpm B. If the ball is being kept in a circular path by the string, then what is the tension in the string? - 5

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section6.2: Circular Motion

Problem 13PP

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