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- 1-Using the Karnaugh Method, design and draw the circuit of the logic circuit that gives the result of the multiplication of the two-bit numbers "AB" and "CD" according to minterms (SOP). Do not make any further simplifications before or after the Karnaugh Method. In tables and Karnaugh, ensure that the least significant bit is on the far right and the entries are sorted alphabetically. Make sure that the circuit you have drawn is understandable, the function you have written and the truth table are readable.Simplify the following Boolean expression after that you will have to draw a logic circuit for the simplified function using only 7 NOR gates: F(K,L,M, N) = Σ (0,3,4,8,11,13) + Σ d(5,9,12,15) Suppose you want to send a BCD number "(100100110101)BCD" to your friend and the sending device has an odd parity bit generator that can process a single BCD digit. Design an odd parity bit generator to send BCD digit and find out parity bit for given number.We need a logic circuit that gives a high output if a given hexadecimal digit is 4, 6, C, or E. The inputs to the logic circuit are the bits B 8, B 4, B 2 and B 1 of the binary equivalent for the hexadecimal digit. (The MSB is B 8 and the LSB is B 1 ) .Construct the Karnaugh map and write the minimized SOP and POS expressions for X.
- Design a combinational logic circuit that converts a three-bit binary number from code A to code B, according to the table on the right. Answer the following questions: Code A Code B 000 000 100 001 110 010 010 011 011 100 001 101 101 110 111 111 Implement your circuit using two 2-by-4 decoders (with enables) only. Explain your implementation. You can use as many ‘OR’ gates and inverters as you need. Implement your circuit using 4-by-1 multiplexers and the fewest number of additional logic gates (if needed). Provide the complete implementation.Design a combinational logic circuit which has one output Z and a 4-bit input ABCD representing a binary number. Z should be 1 iff the input is at least 5, but is no greater than 11. Use one OR gate (three inputs) and three AND gates (with no more than three inputs each.)Please design a 6:1 multiplexer following the below procedures with data inputs of D5, D4, D3,D2, D1, D0 and output of Y.1 How many select signals are needed for this Mux.2) List a truth table for this Mux. Note: for all the unused combinations of select signals, Y=D5Develop an optimized function for this Mux.4Sketch the logic diagram of implementing this 6:1 Mux. Write a complete VHDL structural model to implement the above 6:1 multiplexer. Assume allthe required sub-component (standard gates) VHDL models are given/known that you can use.
- Design a BCD-to-seven Segment decoder that accepts a decimal digit in BCD and generate the corresponding seven-segment code. Inputs from 0000 to 1001 should output their equivalent decimal value, while inputs from 1010 to 1111 should display an output of “E”. Use the truth table below to record your inputs and outputs, then use Karnaugh mapping to determine the equivalent logic circuit/s.For the Logic circuit shown below, Find Expression for F Simplify the expression of Fusing Boolean algebra and De-Morgan's theorems. Draw the logic symbol and truth table of the gate which performs logic addition with inversionDesign a 4-bit arithmetic circuit, with two selection variables S1 and S0, that generates the arithmetic operations in the following table. Draw the logic diagram for a single bit stage. Note that B’ represents “Not B”. Complete the following truth table.
- Q (A, B, C) = A̅ .B̅. C +A̅ .B. C + A .B. C̅ + A.B.C Karnaugh function given in the form Using the mapping method, you can use the simplified function separately in terms of minterms and maxterms. obtain. Output functions with AND NOT for minterms and OR for maxters. Install separately with logic doors.Consider Table P7.40. A, B, and C represent logic-variable input signals; F through K are outputs. Using the product-of-sums approach, write a Boolean expression for F in terms of the inputs. Repeat by using the sum-of-products approach. Repeat Problem P7.40 for I.We need a logic circuit that gives an output X that is high only if a given hexadecimal digit is even (including 0) and less than 7. The inputs to the logic circuit are the bits B 8 , B 4 , B 2 , and B 1 of the binary equivalent for the hexadecimal digit. (The MSB is B 8, and the LSB is B 1 ) Construct a truth table and the Karnaugh map; then, write the minimized SOP expression for X.