Please show all work and do all parts $4IDIRFDA cube with side length 12 cm is oriented parallel to the coordinate planes as shown. The cube isplaced in an external electric field of E= 50i+60j N/C. Calculate the electric flux through thedifferent sides of the cube.Hint: The x-component of the electric field acts left to right, since it is positive. The y-component of the electric field acts from bottom to top, since it is positive. Consider that theelectric field has no z-component.VFlux through the top side =Flux through the left side =Flux through the right side =Flux through the front side = 0Submit Question%5TA6BYG H17 4-&(N*m²)/C(N*m²)/C(N*m²)/C(N*m²)/C+8M(K► 11OL[?prt sc4deletebackspacepause

Answered: 0 A cube with side length 12 cm is…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.46P: A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108...

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Please show all work and do all parts

$
4
IDI
R
F
D
A cube with side length 12 cm is oriented parallel to the coordinate planes as shown. The cube is
placed in an external electric field of E= 50i+60j N/C. Calculate the electric flux through the
different sides of the cube.
Hint: The x-component of the electric field acts left to right, since it is positive. The y-
component of the electric field acts from bottom to top, since it is positive. Consider that the
electric field has no z-component.
V
Flux through the top side =
Flux through the left side =
Flux through the right side =
Flux through the front side = 0
Submit Question
%
5
T
A
6
B
Y
G H
17 4-
&
(N*m²)/C
(N*m²)/C
(N*m²)/C
(N*m²)/C
+
8
M
(
K
► 11
O
L
[
?
prt sc
4
delete
backspace
pause

Expert Solution

Step 1

The flux us given as the dot product of electric field vector and the area vector .

The direction of area vector is prependicularly outward of the surface . If we are looking the cube from its exterior the area vector with each surface is directly outward from that surface .

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