0. How many mL of 0.25M NaOH will be needed to neutralize 20 mL of stomach acid if stomach acid is 0.10 М НС1? NaOH+ HCI → H2O+ NaCl (Im) (1) M(base)V(bases)= (1) M(acid)V(acid)

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.7: Stoichiometry Of Reactions In Aqueous Solution-fundamentals
Problem 2RC: What volume of 0.250 M NaOH is required to react completely with 0.0100 moles of H2SO4? (a) 80.0 mL...
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0. How many mL of 0.25M NaOH will be needed to neutralize 20 mL of stomach acid if stomach acid is 0.10
М НC1?
NaOH + HCl → H2O+ NaCl
(1) M(base)V(bases)= (1) M(acid)V(acid)
(Im)
0) no
Transcribed Image Text:0. How many mL of 0.25M NaOH will be needed to neutralize 20 mL of stomach acid if stomach acid is 0.10 М НC1? NaOH + HCl → H2O+ NaCl (1) M(base)V(bases)= (1) M(acid)V(acid) (Im) 0) no
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