Stomach acid, a dilute solution of HCl in water, can be neutralized by reaction with sodium hydrogen carbonate (NaHCO3) according to the equation HCl + NaHCO3  NaCl + H2O + CO2 How many milliliters of 0.125 M NaHCO3 solution are needed to neutralize 18.0 mL of 0.100 M HCl?

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter4: Reactions In Aqueous Solution
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Problem 38QAP: Lactic acid, C3H6O3 is the acid present in sour milk. A 0.100-g sample of pure lactic acid requires...
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Stomach acid, a dilute solution of HCl in water, can be neutralized by reaction with sodium
hydrogen carbonate (NaHCO3) according to the equation
HCl + NaHCO3  NaCl + H2O + CO2

How many milliliters of 0.125 M NaHCO3 solution are needed to neutralize 18.0 mL of 0.100
M HCl?

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