The 10.00 V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that itspositive terminal is now next to point a. The rest of the circuit is as shown in the figure.For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A complex network.Figure2.00 2 10.00 V,aww+1.00 2 5.00 V14.00 Ω3.00 Ωwww10.00 Ωb1 of 1Find the current through 3.00 resistor.Express your answer with the appropriate units.13.00 2 =SubmitPart B14.00 12 =SubmitPart CFind the current through 4.00 2 resistor.Express your answer with the appropriate units.I10.00 =SubmitPart DValueμARequest AnswerVab =·μAValueRequest AnswerFind the current through 10.00 resistor.Express your answer with the appropriate units.ValueμÃRequest AnswerValueUnitsμACUnitsUnitsFind the potential difference Vab of point a relative to point b.Express your answer with the appropriate units.Units????

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0.00 V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that its e terminal is now next to point a. The rest of the circuit is as shown in the figure. lated problemsolving tips and strategies, you may want to view a Video Tutor Solution of A complex network. 2.00 2 10.00 V a 1.00 25.00 V. 14.00 Ω 10.00 Ω 3.00 Ω b -www- < 1 of 1 > Find the current through 3.00 $2 resistor. Express your answer with the appropriate units. 13.00 = Submit Part B 14.00 12 = Submit Part C Find the current through 4.00 2 resistor. Express your answer with the appropriate units. I10.00 = Part D HA Value Request Answer Vab= O μÀ Value Find the current through 10.00 S2 resistor. Express your answer with the appropriate units. Request Answer Submit Request Answer Value HA Value μА Units 3 Units Units Find the potential difference Vab of point a relative to point b. Express your answer with the appropriate units. Units ? ? ? ?

0.00 V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that its e terminal is now next to point a. The rest of the circuit is as shown in the figure. lated problemsolving tips and strategies, you may want to view a Video Tutor Solution of A complex network. 2.00 2 10.00 V a 1.00 25.00 V. 14.00 Ω 10.00 Ω 3.00 Ω b -www- < 1 of 1 > Find the current through 3.00 $2 resistor. Express your answer with the appropriate units. 13.00 = Submit Part B 14.00 12 = Submit Part C Find the current through 4.00 2 resistor. Express your answer with the appropriate units. I10.00 = Part D HA Value Request Answer Vab= O μÀ Value Find the current through 10.00 S2 resistor. Express your answer with the appropriate units. Request Answer Submit Request Answer Value HA Value μА Units 3 Units Units Find the potential difference Vab of point a relative to point b. Express your answer with the appropriate units. Units ? ? ? ?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 47P: According to its design specification, the timer circuit delaying the closing of an elevator door is...

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A potential difference of 1.00 V is maintained across a 10.0- resistor for a period of 20.0 s. What total charge passes by a point in one of the wires connected to the resistor in this time interval? (a) 200 C (b) 20.0 C (c) 2.00 C (d) 0.005 00 C (e) 0.050 0 C
Electric current I enters a node with three resistors connected in parallel (Fig. CQ18.5). Which one of the following is correct? (a) I1 = I and I2 = I3 = 0. (b) I2 I1 and I2 I3. (c) V1 V2 V3 (d) I1 I2 I3 0. Figure CQ18.5
Electric current I enters a node with three resistors connected in parallel (Fig. CQ18.5). Which one of the following is correct? (a) I1 = I and I2 = I3 = 0. (b) I2 I1 and I2 I3. (c) V1 V2 V3 (d) I1 I2 I3 0. Figure CQ18.5
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Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage Vout from a source voltage . Determine the required value of R2 if = 5.00 V, Vout = 1.50 V and R1 = 1.00 103 (Hint: Use Kirchhoff's loop rule, substituting Vout = IR2, to find the current. Then solve Ohms law for R2. Figure P18.26
(a) What is the average power output of a heart defibrillator that dissipates 400 J of energy in 10.0 ms? (b) Considering the high-power output, why doesn’t the defibrillator produce serious bums?
When the switch is open in Figure 18.8, power Po is delivered to the resistor R1. When the switch is closed, which of the following is true about the power Pc delivered to R1? (Neglect the internal resistance of the battery.) (a) Pc Po (b) Pc = Po (c) Pc Po Figure 18.8 (Quick Quizzes 18.5 and 18.6)
At one instant, a current of 6.0 A flows through part of a circuit as shown in Figure P33.12. Determine the instantaneous potential difference between points A and B if the current starts to decrease at a constant rate of 1.0 102 A/s. FIGURE P33.12
An electric eel generates electric currents through its highly specialized Hunters organ, in which thousands of disk-shaped cells called electrocytes are lined up in series, very much in the same way batteries are lined up inside a flashlight. When activated, each electrocyte can maintain a potential difference of about 150 mV at a current of 1.0 A for about 2.0 ms. Suppose a grown electric eel has 4.0 103 electrocytes and can deliver up to 3.00 102 shocks in rapid series over about 1.0 s. (a) What maximum electrical power can an electric eel generate? (b) Approximately how much energy does it release in one shock? (c) How high would a mass of 1.0 kg have to be lifted so that its gravitational potential energy equals the energy released in 3.00 102 such shocks?
Suppose you need to measure the potential difference between the points in Figure P29.4. Assume the voltmeter reading is the potential difference between the two leads: V = Vred Vblack. For each of the following measurements, determine at which point you would connect the red lead and at which point you would connect the black lead: a. Vb Va. b. Vc Vb. c. Vd Vc. d. Va Vd. FIGURE P29.4 Problems 4, 5, and 6.
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