0.3 m . -9= 10 kPa Re 4.33 m H= 3.20 m D =1.20 m B = 2.20 m g = 1.20 m h = 0.45 m b =0,40 m I= 0.60 m z= 1.00 m P.= 50.7 kN/m Gravelly sand: y= 18 kN/m3 = 33 c = 0 1.21m B VW.T Soft clay:y = 17.5 kN/m3 C= 20 kPa = 0" Sheme 5.97

0.3 m . -9= 10 kPa Re 4.33 m H= 3.20 m D =1.20 m B = 2.20 m g = 1.20 m h = 0.45 m b =0,40 m I= 0.60 m z= 1.00 m P.= 50.7 kN/m Gravelly sand: y= 18 kN/m3 = 33 c = 0 1.21m B VW.T Soft clay:y = 17.5 kN/m3 C= 20 kPa = 0" Sheme 5.97

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter11: Ground Improvement

Section: Chapter Questions

Problem 11.9P

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Question

Assume the base soil and that in front the wall is gravelly sand of Ø = 33 and γ = 18 kN/m3,
overlying a soft-clay deposit at 1.0mdepth belowthe base level, as shown in the scheme below. The ground water table
is also located at the same depth. The soft clay has an average c = 20 kPa,Ø= 0 and γ = 17.5 kN/m3. Determine the
safety factor (SF) against a deep-seated shear failure (or rotational instability) for a trial cylindrical slip surface through
the heel shown in Scheme 5.97. Assume radius of the cylindrical slip surface is 4.33 m, and its centre O located at
2.87 m above the foundation level. Use the conventional method of slices (the Fellenius or Swedish solution).

0.3 m .
-9= 10 kPa
Re 4.33 m
H= 3.20 m
D =1.20 m
B = 2.20 m
g = 1.20 m
h = 0.45 m
b =0,40 m
I= 0.60 m
z= 1.00 m
P.=
50.7 kN/m
Gravelly sand:
y= 18 kN/m3
= 33
c = 0
1.21m
B
VW.T
Soft clay:y = 17.5 kN/m3
C= 20 kPa
= 0"
Sheme 5.97

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