0.5 gr of a diprotic acid is dissolved in water and titrated with 10 ml 1 M KOH to phenolphthalein end point. What is the molar mass of the acid? ½ H2A (aq) + KOH (aq) --> ½ K2A (aq) + H2O () Molar mass of KOH: 56 gr/mol O a 100 gr/mol O b. 200 gr/mol O. 50 gr/mol O d. 150 gr/mol

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
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Chapter16: Applications Of Neutralization Titrations
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Problem 16.20QAP
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0.5 gr of a diprotic acid is dissolved in water and titrated with 10 ml 1 M KOH to phenolphthalein end point. What is the molar mass of the acid?
½ H2A (aq) + KOH (aq) --> ½ K2A (aq) + H20 (1)
Molar mass of KOH: 56 gr/mol
O a. 100 gr/mol
оь. 200 gr/mol
Ос. 50 gr/mol
O d. 150 gr/mol
Transcribed Image Text:0.5 gr of a diprotic acid is dissolved in water and titrated with 10 ml 1 M KOH to phenolphthalein end point. What is the molar mass of the acid? ½ H2A (aq) + KOH (aq) --> ½ K2A (aq) + H20 (1) Molar mass of KOH: 56 gr/mol O a. 100 gr/mol оь. 200 gr/mol Ос. 50 gr/mol O d. 150 gr/mol
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