02 let x = [5 18 9 11 -2-1 0 13 962 1]. Use a commands to do the following 1) Set the positive values of x to zero 2) Set values that are multiples of 3 to 3 3) Multiply the even values of x by 7 4) Extract the values of x that are greater than 5 into a vector called y 5) Select the larger value of x and print it into vector called z
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- 3. Use the input function to ask the user for a positive, whole number. Then use a for loop to generate a vector containing as many elements of the following sequence as the user requested. For example, if the user entered 7 then your program should generate a vector containing: 1/2 3/4 5/6 7/8 9/10 11/12 13/14 The numerator of the sequence starts at 1 and is always odd. The denominator starts at 2 and is always even. Both the numerator and denominator go up by two each time. 4. Vectorize the calculation from the previous question. In other words, write code that creates the same vector as the previous question, but without using any loops.using R Studio. Create a vector containing all the positive even numbers smaller than 200.The numbers should be displayed in decending orderC++ please 3.9.3: Populating a vector with a for loop. Write a for loop to populate vector userGuesses with NUM_GUESSES integers. Read integers using cin. Ex: If NUM_GUESSES is 3 and user enters 9 5 2, then userGuesses is {9, 5, 2}.
- Assume numbers is a vector that contains these integers:2 4 6 8 10Then the following code executes:numbers. resize (9) :numbers. resize (11, 5) ;What does the vector contain now?O 11 1111 11 11 0 0 0 0 2 4 6 8 10000002468 10 5 502 4 6 8 10 0 0 0 0 11 11 11 11 1105500002468 100246810 000055Assume vec1 is a vector that contains these integers:10 20 30 40 50 60 70 80 90 100And vec2 is a vector that contains these integers3 6 9 12 15Then the following code executes:vecl.resize(7):vecl.swap (vec2) ;What do the vectors contain now?Cvec1 contains 3 6 9 12 15vec2 contains 10 20 30 40 50 60 70vec1 contains 3 6 9 12 15 0 0Ovec2 contains 10 20 30 40 50 60 70vec1 contains 3 6 9 12 15O vec2 contains 50 60 70 80 90 100vec1 contains 0 0 3 6 9 12 15O vec2 contains 50 60 70 80 90 100This code creates a compiler error.In C++ please: Read integers from input and store each integer into a vector until 0 is read. Do not store 0 into the vector. Then, output all values in the vector (including the last value) each multiplied by the last value in the vector. Output each value on a new line. Ex: If the input is -63 79 -48 7 0, the output is: -441 553 -336 49 #include <iostream>#include <vector>using namespace std; int main() { //place code herereturn 0;}C++ Help Integers are read from input and stored into a vector until 0 is read. Output the elements from index n to the last index of the vector, where n is specified by the vector's last element. End each number with a newline. Ex: If the input is 7 12 18 2 0, the vector's last element is 2. Thus, the output is: 18 2 Note: The input has at least three integers, and the vector's last element is always less than the vector's size. #include <iostream>#include <vector>using namespace std; int main() { vector<int> intVect; int value; int i; int n; cin >> value; while (value != 0) { intVect.push_back(value); cin >> value; } // insert code here return 0;}
- Question 9 c++ please!! Write a program that stores a list of positive integers from input into a vector and outputs the Nth number from the end of the vector. A negative integer indicates the end of the input and is not stored in the vector. Convert the negative integer read at the end to positive and use as N. Output the negative integer read at the end if the size of the vector is smaller than N. Assume the vector will always contain fewer than 20 integers. Full explainthe this question very fast solution sent me step by step Don't ignore any part all part work u Text typing work only not allow paper workQuestion2: Define an integer vector and ask the user to give you values for the vector. because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). then calculate the average of all numbers he entered. find minimum number in the vector find maximum number in the vector find size of the vector C++ languageQuestion2: Define an integer vector and ask the user to give you values for the vector. because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). then calculate the average of all numbers he entered. find minimum number in the vector find maximum number in the vector find size of the vector
- Fix my C++ code please! Question and code is below as well as error picture. (Duplicate Elimination with vector) Use a vector to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the vector only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Begin with an empty vector and use its push_back function to add each unique value to the vector. My code; #include <iostream>#include <vector> using namespace std;int find(vector<int> &v, int num) { for(int i = 0; i < v.size(); ++i) { if(v[i] == num) { return i; } } return -1;}int main() { vector<int> v; int num; for(int i = 0; i < 20; ++i) { cout << "Enter an Integer : "; cin >> num; if(num >= 10 && num <= 100 && find(v, num) == -1) {…Fix my C++ code please! Question and code is below as well as error picture. (Duplicate Elimination with vector) Use a vector to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the vector only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Begin with an empty vector and use its push_back function to add each unique value to the vector. My code (I think it is missing commas); #include <iostream>#include <vector>using namespace std;int find(vector<int> &v, int num) { for(int i = 0; i < v.size(); ++i) { if(v[i] == num) { return i; } } return -1;}int main() { vector<int> v; int num; for(int i = 0; i < 20; ++i) { cout << "Enter an integer: "; cin >> num; if(num >= 10 && num <= 100 &&…1- Define an integer vector and ask the user to give you values for the vector. because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). the calculate the average of all numbers he entered. 2- Write a program that asks the user to enter integers as the width and length of a rectangle that should be stored in the variables 'a' and 'b' respectively. There are also two integer pointers named ptrA and ptrB. Assign the values of 'a' and 'b' to ptrA and ptrB respectively, Calculate the are and perimeter of the rectangle by using these pointers.