C++ please 3.9.3: Populating a vector with a for loop.   Write a for loop to populate vector userGuesses with NUM_GUESSES integers. Read integers using cin. Ex: If NUM_GUESSES is 3 and user enters 9 5 2, then userGuesses is {9, 5, 2}.

In C++, define an integer vector and ask the user to give you values for the vector. Because you used a vector, so you don't need to know the size. user should be able to enter a number until he wants(you can use while loop for termination. for example if the user enters any negative number, but until he enters a positive number, your program should read and push it inside of the vector). the calculate the average of all numbers he entered.

Using C++ Using only these simpler vector methods Create a vector of at least 10 integers. Cout the vector with spaces in between the integers. Cout the vector backward. Using loops that traverse the elements, create a new vector with the elements arranged from high to low. Cout the new vector. Do not use iterators for this exercise, or any other advanced methods--only the ones listed below.   Hint: Use multiple vectors, including the copying of vectors. vector<int> grades1 = {45, 67, 88, 45, 23}; vector<int> grades2 = grades1;     May Only Use These Vector Methods:   size()                              // Returns the number of elements empty()                         // Returns a boolean True if the vector is empty   push_back(element)    // Adds an element to the back of the vector pop_back()                    // Removes the element at the back of the vector   front()                             // Returns the element at the front of the vector back()…

C++ Program For this program you’ll write a simple class and use it in a vector.Begin by writing a Student class. The public section has the following methods: Student::Student()Constructor. Initializes all data elements: name to empty string(s), numeric variables to 0. bool Student::ReadData(istream& in)Data input. The istream should already be open. Reads the following data, in this order: First name (a string, 1 word) Last name (also a string, also 1 word) 5 quiz scores (integers, range 0-20) 3 exam scores (integers, range 0-100) Assumes that all data is separated by whitespace. The method returns true if reading all data was successful, otherwise returns false. Does not need to validate or range-check data; if one of the quiz or exam scores is out of range, just keep going. bool Student::WriteData(ostream& out) constOutput function. Writes data in the following format. Each student’s data is on one line. • First name (left justified, 20 characters)• Last name (left…

C++

C++ Dynamic Array Project Part 2

Answer in C++ code please! (Duplicate Elimination with vector) Use a vector to solve the following problem. Read in 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, validate it and store it in the vector only if it isn't a duplicate of a number already read. After reading all the values, display only the unique values that the user entered. Begin with an empty vector and use its push_back function to add each unique value to the vector.

In C++ Create an array of head pointers, statically allocated of size 101 of that type: Now, create a pointer that can point to the first element: Show how to dynamically allocate an array of 101 elements of head pointers: Write the code to initialize each element to NULL: Rewrite the code to initialize each element to NULL using pointer arithmetic:

Create a flowchart for this program in c++, #include <iostream>#include <vector> // for vectors#include <algorithm>#include <cmath> // math for function like pow ,sin, log#include <numeric>using std::vector;using namespace std;int main(){    vector <float> x, y;//vector x for x and y for y    float x_tmp = -2.5; // initial value of x    float my_function(float x);    while (x_tmp <= 2.5) // the last value of x    {        x.push_back(x_tmp);        y.push_back(my_function(x_tmp)); // calculate function's value for given x        x_tmp += 1;// add step     }    cout << "my name's khaled , my variant is 21 ," << " my function is y = 0.05 * x^3 + 6sin(3x) + 4 " << endl;    cout << "x\t";    for (auto x_tmp1 : x)        cout << '\t' << x_tmp1;//printing x values with tops    cout << endl;    cout << "y\t";    for (auto y_tmp1 : y)        cout << '\t' << y_tmp1;//printing y values with tops…

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