(05): Calculate the value of resistance Rs (in 2) when the dissipated power delivered to the external (load) resistances is maximum.

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Chapter21: Circuits And Dc Instruments
Section: Chapter Questions
Problem 76PE: Integrated Concepts A 160F capacitor charged to 450 V is discharged through a 31.2-k resistor. (a)...
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Q 5 please
3- Power Transfer
In this experiment three resistors are connected with a
battery V, 12V with internal resistance Rs. If R₁-2 2,
R₂ 8 2 and R3-3.4 2.
(05): Calculate the value of resistance Rs (in 2) when
the dissipated power delivered to the external (load)
resistances is maximum.
(a.) 4
b. 5
b. 1.5
C.
4-Wheatstone Bridge:
The shown figure below is a
Wheatstone-bridge set up. At a length x
the galvanometer gives no deflection.
(there is no current through the
galvanometer).
3
c. 1.2
(06): The current I (in A) in the shown circuit when the power dissipated through RL is
maximum equals:
a. 3A
R₁3
C.
Good Luck
R4
ww
(07): If the ratio R4/R3 is 0.5, then the value of x (in cm) is
a.) 25
b. 15
C. 50 cm
X
R₂
Vs
d. 2
75cm
d. 2
d. 60
R3
(08): If the bridge is balanced (when there is no current through the galvanometer) when
R4=4 2 and R₁=2 2. If the potential difference AVAD equals 4V, then the total current I is
a. 9A
b. 6A
12A
a. 3A
R₂
75-x
R
Transcribed Image Text:3- Power Transfer In this experiment three resistors are connected with a battery V, 12V with internal resistance Rs. If R₁-2 2, R₂ 8 2 and R3-3.4 2. (05): Calculate the value of resistance Rs (in 2) when the dissipated power delivered to the external (load) resistances is maximum. (a.) 4 b. 5 b. 1.5 C. 4-Wheatstone Bridge: The shown figure below is a Wheatstone-bridge set up. At a length x the galvanometer gives no deflection. (there is no current through the galvanometer). 3 c. 1.2 (06): The current I (in A) in the shown circuit when the power dissipated through RL is maximum equals: a. 3A R₁3 C. Good Luck R4 ww (07): If the ratio R4/R3 is 0.5, then the value of x (in cm) is a.) 25 b. 15 C. 50 cm X R₂ Vs d. 2 75cm d. 2 d. 60 R3 (08): If the bridge is balanced (when there is no current through the galvanometer) when R4=4 2 and R₁=2 2. If the potential difference AVAD equals 4V, then the total current I is a. 9A b. 6A 12A a. 3A R₂ 75-x R
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