1 .For a direct shear test on a dry sand, the following are given: • Specimen size: 75 mm 75 mm 30 mm (height) • Normal stress: 200 kN/m2 • Shear stress at failure: 175 kN/m2 a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure? in the specime

1 .For a direct shear test on a dry sand, the following are given: • Specimen size: 75 mm 75 mm 30 mm (height) • Normal stress: 200 kN/m2 • Shear stress at failure: 175 kN/m2 a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure? in the specime

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter10: Shear Strength Of Soil

Section: Chapter Questions

Problem 10.10P

See similar textbooks

Similar questions

Refer to the flexible loaded rectangular area shown in Figure 10.47. Using Eq. (10.36), determine the vertical stress increase below the center of the loaded area at depths z = 3, 6, 9, 12, and 15 m. Figure 10.47
For the same line loads given in Problem 10.8, determine the vertical stress increase, z, at a point located 4 m below the line load, q2. Refer to Figure 10.41. Determine the vertical stress increase, z, at point A with the following values: q1 = 110 kN/m, q2 = 440 kN/m, x1 = 6 m, x2 = 3 m, and z = 4 m. Figure 10.41
The following data are given for a direct shear test conducted on dry sand:- Specimen dimensions: 75 mm X 75 mm X 30 mm (height)- Normal stress: 200 kN/m2- Shear stress at failure: 175 kN/m2a) Determine the angle of friction,b) For a normal stress of 150 kN/m2, what shear force is required to cause failure?
A sample of ocean sand was retrieved from 7 m below the surface. The sample had been under a vertical stress Ov of 150 kN/m³, a horizontal stress Oh of 250 kN/m³, a shear stress of 86.6 kN/m. If the angle theta between the vertical stress and the principal stress is 60°, calculate the angle of internal friction of the soil. [Hint: you must sketch the Mohr circle of stresses] Please explain clearly and step by step
A sample was obtained from point A in the submerged clay layer shown below. It was determined that it had a w = 54%, and a Gs = 2.78. What is the effective vertical stress at A? Express your answer in kPa rounded to the nearest whole number.
he following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and b
A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Show diagram
The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf = 100 kN/m2 Shear Stress τf = 40 kN/m2 Required: a) Determine the angle of internal friction and angle of failure plane b) Find the major and minor principle stresses (1 , 3 )
In a drained triaxial test on consolidated clay the stress and angle are as follows : Deviator stress is 20 lb/in2 and friction angle 210 . calculate the effective confining pressure at failure.?
A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa.
A direct shear test was conducted on a specimen of dry sand with a normal stress of 200 kN/m2. Failure occurred at a shear stress of 175 kN/m2. The size of the specimen testedwas 75 mm × 75 mm × 30 mm (height). Determine the angle of friction, . For a normal stress of 150 kN/m2, what shear force would be required to cause failure of the specimen?
Following data are given for a direct shear test conducted on dry silty sand:Specimen dimensions: diameter = 71 mm; height = 25 mmNormal stress: 150 kN/m2Shear force at failure: 276 N