(1) 0.8 (2) -0.8 (3) I (4) -1 01 0 2 04

Q: 1 -1/2R2 = R2 1 1 1 1/32R3 = R3 1 1 1 1 1 1 -1/5R4 = R4 1 1 1 1 1 1 1

A:

Q: 2 0 A=4 0 0 0 (b) - 2 1 4 5 2 2 1 3 0 13 2 2 (c) A= -

A: This question is related to vector space . solve in step 2.

Q: 1 3 -4 2 0 0 0 0 0 0 0 0 -1 6. 1 -3 7 1 4 -3 0 0

A: Remark:  We know that the maximum number of linearly independent vectors in a matrix is equal to the…

Q: 4. P(-0.93 <z< 0) 5. P(z < 1.50) 6. P(-2.37 <z<-0.37)

A: Let z follows the normal distribution then,  We will find the above probabilities= ?

Q: Find the determinant of the matrix.

A: We use the Laplace expansion to find the determinant of A= 120003400000123002-110013-1 Consider the…

Q: -2 7 6 -3 0 08-5 A = 35 8 53 4. Find M13 and C13. M13= C13= i 48

A: Minor of an element of aij of the determinant of matrix A is obtained by deleting ith row and jth…

Q: 1 0 0 0 0 1 2 -6 2 -8 10 1 0 1 0 3 -2 -5 -16 |

A: We have to multiply: 1000012-60010003-22-8-5-16

Q: 2а - 1 2а? - 5а + 4 За - 2, 2а - 3 8а? - 22а + 15 4а-5 O 3 7 1 2а - 3 2а? - ба +15 8a? - 22а + 15 II

A:

Q: * Q1 1 |1 2 31 -1 -1 0 21 3 -3 11 14 5 -71 -41 -7] -14] 2. -11 3. 5 -7 5] 5. 1 2 3 1. 4.

A:

Q: 1 0 0 0 1 -1 0 0 0 -1 - (Ь.) А — 1 -1 0 0 -1 0 -1 0 0 0 0 -1 1 0 0 1 - 1

A: Given: A=100001-100-11-100-10000-1-11001 To find: Jordan Canonical form of the matrices.

Q: 1 1 0 2 1 1 B = |-1 2 1 1 0 0 1 2

A: We have the given matrix :  B=1102-12111012 First we have to find the basis for the col(B) . Next we…

Q: 0 0 01 |-1 2 0 7 3. 7 i 3

A: The given matrix,0000-12007070i301

Q: 6s – 5 4s +7 3s – 2 s +8s+ 25 ) s+7 s(s² – 3s – 10) naL 3²L² +n?n?

A:

Q: T 3 0 0 ? 0 2 [ 2 2 0 0. 0. 0 2 2 0 2 0 3 3 0 -2 | 2 -2 2 0 3 0 0 0 -1 4 -2 -2 -2 3

A: Explanation of the solution is given below...

Q: P(-0.5 < z  < 0.13)=

A: Given information- We have given the normal distribution. We have to find the probability. P(-0.5…

Q: Ž (1 – p)?k=1 = -P- Ž (1 – p)²k 2k-1 Ë (1 – p) | 1- P k=1 k=1

A: Considering the LHS looping the values from 1 to 4 ∑k=1∞(1-p)2k-1 = 11-p∑k=1∞(1-p)2k LHS…

Q: ompute 0 0 O0 3000 (3 3 3 3 3 3 3 3 3 0 0 0 0 0 0 0 0 0 F (3) B Otherwise (0) DI 13

A: To find the given matrix multiplication

Q: /courses/3050521/quizzes/6952222/take 6- 5- 4+-- B' 1 -11-10-9 -8 -7 -6 -5 2 3 4 -3-2 -A 0 1 01 -2…

A:

Q: 7) y=--x – 2 2 8) y=x- 3 3 y = --x + 2 y = -x + 1 y to 3 -o -3 Answer: Answer:

A: 7) The given system of the equation is y=-x2-2y=-3x2+2.

Q: (3) 2.3-= 3" – 1 i=1 k+1 Hint: 2-3-1 = 2-3i-1+2-3'k+1)-1 = 3* –1+2-3* = 3-3* –1 = 3*+1_1 i=1 i=1

A: ∑i=1n2.3i-1=3n-1for  n=1∑i=1n2.3i-1=2.30=2=31-1,    truefor n=2∑i=1n2.3i-1=2.30+2.31=2+6=8=32-1,…

Q: 1 0 1 0 -1 1 0 1 -1 0 0 1 0 -1 0 1]

A:

Q: 1 0 2 -2 3 1 3X +|2 1 3 -1 -2 0 4 -1 5 1 5 II

A: The given equation is,

Q: 123 A= 4 5 6 7 8 9 -1 7 3 B= 4 -2 5 -3 9 4 13 2 C= 6. 0 10 3 6. DD 2 L-7 8 4 F- 8. %3D

A:

Q: 0.2 0.1 0.3 0.3 0.6 0.3 43. Р 3D 0.1 0.2 0.2 0.4 0.1 0.2

A: Given:  P=10.20.10.300.30.60.300.10.20.200.40.10.2To find : steady state matrix X of the absorbing…

Q: -5 4 0 1 0 * 0 * 0 1 0. 0. . 1 0. 8. 0. 2 0.

A:

Q: 2. 1. 2 8. 2. -2 そ %3D 00 11 元N ゴ

A:

Q: Y 1 -1 2 2 -2 -6 3 2 4 3 2 10 3 14 4 7 4 {(4,1) (3, 1)(0, 3)(-7,5)} 2. CO

A:

Q: Between z=1.40 and z=2.03

A: We have to find area between z=1.40 and z=2.03

Q: : p(y-2|<10) p(z <2) =0.9772 y- N(2,25) 0.4594 0.5944 O 0.9544

A: It is known that, Z score= (y-mean)/standard deviation. Given that, Mean= 2 and variance= 25  So…

Q: 5(1+2n)=15

A: This question is based on Algebraic operation.

Q: Mutiply : 3(9/20) x 2(1/12) = ? 17 x 1(3/34)=? 1(11/24) x 16 =  10/39 x 2(3/5)=?

A: We can do these multiplications as below

Q: 0 2५+ 3५-2५-० 24 +4== 364-3647134-

A:

Q: 5 2 0 3 1 3 В с 4 -4 -1 0 5 0 1 1 1 -4 СА

A: Given,

Q: iii) P(-0.20 z-.50) 0.1122 O-0.1122 0.8878

A: Z-score is normally distributed with mean 0 and variance 1.

Q: -1- -314 -1/2 -1)4 14 1/2 3/14 5/14 3/2 7/14 AWWW -1H 3 f(x)

A: Lets go step by step  The graph looks like inverted cosine with amplitude of 2 units So the graph of…

Q: Use the matrix P to show that the matrices A and A′ are similar.

A:

Q: [1 3 17 TO 1 2] 2( اذا كانت 1 0 1-=B A= 2 0 1 3 1 2 510 تحق ق من أن :

A: find the determinant of the matrix A

Q: 2. p (x) = 2 x- 3 x-6 x³+9 x?+8 x- 12, by x+½

A:

Q: -2 3 0 71 -1 0 0 0 3 0 0 -1 3 0 00 5 3 2 5 3 0 0 If A = -3 4 5 6 -

A:

Q: r2 1, 2.0 2.0 1.5 1.5 10 10 0.5 0.5 O-2 -1 1 O-2 -1 1 -2 -2 -0.5 -0.5 -1.5 -1.5 - 2.0 -2.0

A:

Q: A = 5 0 0 0 -6 -1 -1 0060 0 0 -11 -5 - 11

A:

Q: 1 -2 0 2 0 0 1 5 0 -3 0 0 0 1 0 0 0 0 1 1

A: Given Augmented Matrix:- 1-2020100150-30000160000001-110 To solve the augmented matrix

Q: -5 1 0 1 -6 1 0 1 0 -5 1 -6 0 5 2 0 A = 3 -1 0 6 -2 0 2 5

A:

Q: Between z= 0 and z= 3.18

A: we have to find the area Between z= 0 and z= 3.18

Q: p(-1.80<z<0.20)

A: We have to find P(-1.80&lt;z&lt;0.20)  z is standard normal variable with mean 0 and standard…

Q: 0 |-6 4 13 11 18 17 0 31 9 0

A:

Q: P(-0.63<Z<1.85)=

A: Given : z₁=-0.63 z₂=1.85

Q: Compute the determinant of

A: We know that determinant of upper (lower) triangular matrix is the product of the diagonal entries.

Q: 6. Between z= -1.53 and z=0

A: