-2 3 0 71 -1 0 0 0 3 0 0 -1 3 0 00 5 3 2 5 3 0 0 If A = -3 4 5 6 -

Q: -5 2 3 5 1 1 -3 If A = -3 2 4 and B =-2 6 -3, find BA and AB. -2 1 -1 2

A: Topic :- matrix

Q: 1 3 -4 2 0 0 0 0 0 0 0 0 -1 6. 1 -3 7 1 4 -3 0 0

A: Remark:  We know that the maximum number of linearly independent vectors in a matrix is equal to the…

Q: -1 3 5 -3 -2 1 0 4 -2 5 0 0 ㅇ If A find the following: = 1

A: We will solve the following.

Q: -0.8d + 20 – 8d – 15 3w – 1.25w + 4.45y+ 2y 4 + 7'5 3 5 5 3 1 3 4 6 -9x + 1.8 + 6x – 0.3 – 1.5

A: Note : According to the guidelines only three parts will be answered please upload other parts…

Q: 2 e 1 if A- |-1 3-2) -2 10 -1 3 then D - 124) 2 3 0 5 5 -1 Di 4 2 4 -1 -5

A:

Q: 2. + -+- 1.3 3.5 5.7 + + 1 n (2n-1)(2n+1) 2n+1

A: As per guidelines, I can do first question only.

Q: 4. P(-0.93 <z< 0) 5. P(z < 1.50) 6. P(-2.37 <z<-0.37)

A: Let z follows the normal distribution then,  We will find the above probabilities= ?

Q: -2 1. A = 3 -4 1 det(A) = 0 1 3 -1 1 2.

A: We will use the properties of determinant

Q: 5. for z > -1.34 6, for z <-2.26 7. to the right of z = 1.76

A:

Q: If  A = [ 1   0   0   0 ]      [ -4   1   0   0 ]        [ 1  -1   1   0 ]        [ 7  -2  1   1 ]…

A:

Q: 1 0 0 0 0 1 2 -6 2 -8 10 1 0 1 0 3 -2 -5 -16 |

A: We have to multiply: 1000012-60010003-22-8-5-16

Q: -3 -3 4 -9 ol 0 1 21 -2 3 1 D = 6 9 - A =| 3 |-2 -2 110 3 [3 0 0 F = 0 6 0 lo o -4 5 5 2 -1 E = -4…

A:

Q: 2а - 1 2а? - 5а + 4 За - 2, 2а - 3 8а? - 22а + 15 4а-5 O 3 7 1 2а - 3 2а? - ба +15 8a? - 22а + 15 II

A:

Q: 0 0 01 |-1 2 0 7 3. 7 i 3

A: The given matrix,0000-12007070i301

Q: P(-0.5 < z  < 0.13)=

A: Given information- We have given the normal distribution. We have to find the probability. P(-0.5…

Q: A =  -1 0 2     0 −2 −1 3 4 5             B =  2 -1 −1     0 3 3 −1 0 1 Find A−1B

A: A =  -1 0 2     0 −2 −1 3 4 5         B =  2 -1 −1     0 3 3 −1 0 1 Find A-1B

Q: 구 0.24 9. -3. 18477 21 1.25+22.5 3.구 =IN

A:

Q: -1 1 2 A 3 3 4 det A 0 0 -2 0 0 2 4 B = -5 6. 1 5 3 3 det B: -1 0 0 0 3 0 0 C = 2 0 0 4 0 0 0 0 -2…

A:

Q: 4) P(Z > -0.28) 5) P(1.59 < Z < 3.11) 6) P(-0.74 < Z< 1.74)

A: find the given probabilities?given z be a standard normal random variable with mean 0 and standard…

Q: 4. z = -1.26 to z = 1.45 5. z = - 2 to z = 1.15

A:

Q: 123 A= 4 5 6 7 8 9 -1 7 3 B= 4 -2 5 -3 9 4 13 2 C= 6. 0 10 3 6. DD 2 L-7 8 4 F- 8. %3D

A:

Q: 0 -2 0.5 3 1 -1 A = 2 B = 0 -0.25 and C = 1 1 1 1 -3 2 -1 -1 A+в - с

A: Given,          A=0-22011 ; B=0.530-0.25-32 , and C=1-111-1-1

Q: -5 4 0 1 0 * 0 * 0 1 0. 0. . 1 0. 8. 0. 2 0.

A:

Q: -3 –1 -5 What is -4 2 3 -2 .a 3 2 -7 4 .b 3 -8- | -7 4 .C 1 2 -7 4 .d 3 2 -7 0

A: Two matrices can only be added, if and only if, the dimensions of both matrices are the same. If a…

Q: 2x-26(5-+ 25=0 1 25 0 2文+1 26 (5*) +5 = 0 2. 3(3)+e(3*)-3= 0 12

A:

Q: -2 1 (a) 5 -7 1 6. 2 1 3 3 2 5 0 0 (b) 0 3 2 15 4 0 1 2 1 1 4. 3.

A: Let's find the value of the determinant…

Q: -3 -5 1 7 1 0 -9 7 -5 -3 If A = 0 0 4 7 3 0 0 0 -6 -4 0 0 0 0 -5 then det (A)

A:

Q: Between z=1.40 and z=2.03

A: We have to find area between z=1.40 and z=2.03

Q: Between z= 0.32 and z= 1.92

A: The z score is used to give the probability areas under normal normal curve.  P( a&lt; z&lt;b) = P(…

Q: P(z-1.45)= P(-1.88<z<0.5)= P(-0.69<z<0.69)=

A:

Q: -1 0 3 5 -3 -2 1 If A find the following: = 1 0 4 5 0 0 -2

A: Given:

Q: (1) 0.8 (2) -0.8 (3) I (4) -1 01 0 2 04

A: The correct answer is, Option (1) 0.8   The detailed explanation is as follows below:

Q: -3 0 5] 1-3 0 5 18) 00 0 1 1 00 0 0 0 A) 5 B) 4 C) 3 D) 2

A: Consider the matrix

Q: -1- -314 -1/2 -1)4 14 1/2 3/14 5/14 3/2 7/14 AWWW -1H 3 f(x)

A: Lets go step by step  The graph looks like inverted cosine with amplitude of 2 units So the graph of…

Q: 10 -2 1 0 1 4 0 0 - 15 10 -2 1 0 1 4 0 0 5 -15

A:

Q: correct answer)? 0 0 1 -2 0 1 2 0 2 0 1 1 1 0 0 1 0 -2 0 1 1 0 -2 0 1

A: An elementary matrix is a square matrix that has been obtained by performing an elementary row or…

Q: Find A-1

A: We get the co-factor matrix as cof(A)= -104-137-110-52-11 Now adj(A)= -107-54-12-1310-11

Q: Evaluate:

A: Given dett-101-2t-100t+1

Q: r2 1, 2.0 2.0 1.5 1.5 10 10 0.5 0.5 O-2 -1 1 O-2 -1 1 -2 -2 -0.5 -0.5 -1.5 -1.5 - 2.0 -2.0

A:

Q: -2 6 Find A for A = 3 -3 4 -7 3 s 5/12 /5 1/6 L/S 16 7/20 1/10 1/10 Ans.

A: To find the inverse of matrix A.

Q: 1 -2 0 2 0 0 1 5 0 -3 0 0 0 1 0 0 0 0 1 1

A: Given Augmented Matrix:- 1-2020100150-30000160000001-110 To solve the augmented matrix

Q: 0 |-6 4 13 11 18 17 0 31 9 0

A:

Q: AY -2 +4 if - 3 3 -I+5 6 5 4F 3 2 1 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 -1 -2 -3 -4 -5 -6 -7F

A:

Q: (-0.1)-금 (30)+ (150) f-0.1)= 2 3. (-0.1) 3(-0.1) -0.)(120)=683 6. 4

A: Here we have to go back to just previous step were we have function,…

Q: -3 -1 -3 0 6 B = [ :1. A= -3 14 5 3 0 -21 .c = | -1 3 4 v =| 1 u = [1 -2 0] 2 35

A: Given matrices are A=1-30-31000-2   B=-1-3064530   C=1-1341235 v=31-1   u=1-20 Problem 1: The…

Q: 0. -4 -5 0 -6 -8 11 A = 4 -9 2 -3 det A = Ex: 5

A: