1) 12, NaOH, H20 2 OH + ICH3 2 2) Hо* Draw a detailed mechanism with arrows showing the movement of electrons for the formation of benzoic acid and iodoform from 1,3-diphenyl-1,3-propanedione

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter22: Carbonyl Alpha-substitution Reactions
Section22.SE: Something Extra
Problem 31MP: The Favorskii reaction involves treatment of an -bromo ketone with base to yield a ring-contracted...
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1) l2, NaOH, H2O
2
OH + ICH3
2
2) H30*
Draw a detailed mechanism with arrows showing the movement of electrons for
the formation of benzoic acid and iodoform from 1,3-diphenyl-1,3-propanedione
Transcribed Image Text:1) l2, NaOH, H2O 2 OH + ICH3 2 2) H30* Draw a detailed mechanism with arrows showing the movement of electrons for the formation of benzoic acid and iodoform from 1,3-diphenyl-1,3-propanedione
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