4. In the middle of the selenoid with a diameter of D = 2 cm, length L= 20 cm and consisting ofN1 = 1200 turns there is a small coil with a diameter of d = 1 cm. The length of this small coilis l= 2 cm and consists of N2 = 50 turnsa. Calculate the mutual inductance between the coils.b. If the current in the şelenoid changes at a rate of 0.5 A / s, calculate the emf induced ɛon the small coil.

Given values:- Diameter of the bigger coil,(D)=2 cm=0.02 m ----(1) Length of the solenoid,(L)=20…

1 = 1200 turns there is a small coil with a diameter of d = 1 cm. The length of this small |= 2 cm and consists of N2 = 50 turns . Calculate the mutual inductance between the coils. . If the current in the selenoid changes at a rate of 0.5 A/s, calculate the emf induced

1 = 1200 turns there is a small coil with a diameter of d = 1 cm. The length of this small |= 2 cm and consists of N2 = 50 turns . Calculate the mutual inductance between the coils. . If the current in the selenoid changes at a rate of 0.5 A/s, calculate the emf induced

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter32: Inductance

Section: Chapter Questions

Problem 32.8P

See similar textbooks

Related questions

Q: An emf of 0.60 V is induced across a coil when the current through it changes uniformly from 0.30 to…

Q: An emf of 0.80 Vv is induced across a coil when the current through it changes uniformly from 0.30…

Q: (II) A coil has 2.25 Ω resistance and 112-mH inductance.If the current is 3.00 A and is increasing…

A: The expression for find potential difference across the coil is ∆V=IR+L∆I∆t

Q: A coil of resistance 15Ω and inductance 0.6H is connected to a 120V D.C. line. At what rate will…

A: (a) The expression for the current flowing through the inductor in RL circuit is written as, Here,…

Q: 1: The self-inductance of a coil of 500 turns is 0.25h. If 60% of the flux penetrates into the last…

A: Given, a coil having, N1= 500 N2= 10000 L1= 0.25 H ϕ2=0.6ϕ1 (As, 60% of the flux is linked with…

Q: induced emf (in volts) in the 15-turn coil as a function of time.

A: We know that, ε=-dϕdt......Faraday's lawwhere, ϕ is magnetic flux ε is induced emfThis law gives us…

Q: A coil having 50 turns and an outer and inner diameter of 3cm and 2 cm respectively swings from a…

Q: 5 sin(wt). Inside the solenoid 4) A long solenoid has n=1000 turns per meter and a current I with a=…

Q: Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at…

Q: en the current in one coil changes at a rate of 7.0 A/s, an emf of -9.5 x 10-3 v is induced in a…

Q: A long solenoid with n=18 turns per centimeter has a cross-sectional area of 3.0cm^2, and carries a…

Q: An emf of 5.7 x 10 -3 V is induced in a coil while the current in a nearby coil is decreasing at a…

A: Using the relation between induced emf and iductance,

Q: A long solenoid has a cross-sectional area of 3.00 cm?. The current through the windings is…

Q: 4) A long solenoid has n=800 turns per meter and a current I = 2 sin(wt). Inside the solenoid with…

Q: The current in a coil drops from 4.2 A to 2.8 A in 0.51 s. If the average emf induced in the coil is…

A: Given: The initial current in the coil is 4.2 A. The final current in the coil is 2.8 A. The time…

Q: The current in a coil changes from 3.60 A to 1.90 A in the same direction in 0.510 s. If the average…

A: Given data : Current , I1 = 3.60AI2 = 1.90A…

Q: 4) A long solenoid has n=1000 turns per meter and a current I = 5 sin(wt). Inside the solenoid with…

A: Given: n = 1000 turns per meter; I = 5 sin(wt) a = 0.5 m; b= 0.2 m; Nc = 300 turns; t = 2s; R = 2…

Q: A toroidal solenoid has 550 turns, cross-sectional area 6.40 cm^2, and mean radius 4.60 cm. Part A…

A: Given information: Here, N is the number of turns of the toroidal solenoid, A is the…

Q: A toroidal solenoid has 500 turns, cross-sectional area 6.25 cm2, and mean radius 4.00 cm. (a)…

A: (a) Write the formula for the self-inductance of the rectangular toroid.

Q: 5.5 A hollow air cored inductor coil consist of 500 turns of copper wire which produces a magnetic…

A: We know that Magnetic flux = self inductance × current Here, Magnetic flux = 10 m Wb Current =…

Q: Suppose we have a rectangular loop S2 made by a conducting material with N2 =60turns and length,…

Q: An emf of 121.5 mV is induced in the windings of a coil when the current in a nearby coil is…

A: The formula for the induced emf in term of mutual inductance is:

Q: A 110 V direct current motor generates a back-emf of 98 V when it runs at full speed. If the…

Q: A thin wire is tightly wrapped around a dowel (a wooden cylinder of radius 5.49 cm, length 0.28 m)…

A: Given that: Radius of the cylinder, r= 5.49 cm = 0.0549 mLength, l= 0.28 mNumber of turns in each…

Q: The current in a coil drops from 3.8 A to 1.9 A in 0.52 s. If the average emf induced in the coil is…

A: The self induction of the coil is 3.28 mH

Q: The inductance of a closely packed coil of 400 turns is 6.5 mH. Calculate the magnetic flux (per…

A: The coil with 400 turns can be considered as a solenoid. The expression for inductance of a solenoid…

Q: The current through a coil as a function of time is represented by the equation I(t) = Ae sin(wt),…

A: Induced emf due to the varying current in the first coil…

Q: Suppose that a rectangular toroid has 1, 400 windings and a self-inductance of 0.040 H. If h = 0.13…

A: Explanation and solution shown in the picture below ?

Q: Two coils, 1 and 2, are separated in space, and have a fixed distance between them. When coil 2 has…

A: Given - Rate of increase of current in coil -1, di1/dt = 24.0 A/s EMF induced in coil -2 due…

Q: An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is…

Q: Calculate the inductance (H) of an air cored coil that has a length of 11 cm, a core with…

Q: A voltage of 0.35 V is induced across a coil when the current through it changes uniformly from 0.1…

Q: A toroidal solenoid has 800 turns, cross-sectional area of 16.25 cm^2, and an average radius of…

A: Number of turns in the toroid, N=800 The cross-sectional area of the toroid, A=16.25 cm2 The…

Q: A coil with a self-inductance of 3.0 H carries a current that decreases at a uniform rate dI/dt =…

Q: 4) A coil of N=40 turns and radius 0.5 m surrounds a long solenoid of radius 0.1 m and n=800 turns…

Q: A steady current of 5 A is flowing through an inductor with 90 volts across it. Find (a) Inductance…

A: In the given question given that, current flowing through the inductor is 5amp and and voltage…

Q: At t = 0, an emf of 420 V is applied to a coil that has an inductance of 0.780 H and a resistance of…

A: Let the maximum current be io Given that Resistance (R)= 30 ohm Emf (E)= 420 v Inductance (L)= 0.780…

Q: Figure Q3(a) Calculate the inductance of the coil shown in Figure Q3(b), which has a cylindrical…

A: Given Number of turns of the coil N= 200 Length l =200mm = 0.2 meters Diameter d=5mm Then radius…

Q: 4) A long solenoid has n=1000 turns per meter and a current I = 5 sin(wt). Inside the solenoid with…

A: Given: n= 1000 turns per meter; I = 5 sin(wt) a= 0.5 m; b= 0.2m; Nc = 300 turns; t = 2s; R = 2 ohm

Q: A circular coil has 250 turns and radius 1.50 cm. When a current of 5.00 A flows in the coil, the…

A: Given, Number of turns n=250 Radius R=1.50 cm Current I=5.00 A Magnetic flux density B=0.050 T

Concept explainers

Voltage Across Inductor

An actor is a passive electrical component that consists of a coil bent in the form of wire which uses electromagnetism to produce electric current through the coil. When the electric current flows through a conductor that is the coil, a magnetic flux is developed around the conductor. This flow of current through the coil creates a magnetic field based on Fleming's Right-hand thumb rule. If there is any decrease in the current passing through the inductor, then the magnetic field will also decrease and energy is released through the generation of electric current. There is also a secondary voltage inducing in the same coil due to the magnetic flux, since it opposes any changes in the electric current flowing through the circuit. An inductor is also called choke, coil, or solenoid. A choke is designed to block certain frequencies when the DC current passes. A winding coil is coated with insulation to give extra insulation and protect the circuit. They are usually tightly wrapped around a central core which is cylindrical in nature so that the magnetic flux can be induced. The solenoid is a three-dimension coil that is used to exhibit electromagnetism when the magnetic field is developed due to the current flowing through the coil. The sign convention of the inductor is the same as the power dissipating device. When the current flows into the positive side of the voltage across the inductor, the value is positive and the inductor dissipates power whereas when the inductor releases the power back to the circuit, the current has a negative sign convention. 

Question

4. In the middle of the selenoid with a diameter of D = 2 cm, length L= 20 cm and consisting of
N1 = 1200 turns there is a small coil with a diameter of d = 1 cm. The length of this small coil
is l= 2 cm and consists of N2 = 50 turns
a. Calculate the mutual inductance between the coils.
b. If the current in the şelenoid changes at a rate of 0.5 A / s, calculate the emf induced ɛ
on the small coil.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

(a) If the emf of a coil rotating in a magnetic field is zero at t = 0, and increases to its first peak at t = 0.100 ms, what is the angular velocity of the coil? (b) At what time will its next maximum occur? (c) What is the period of the output? (d) When is the output first one-fourth at its maximum? (e) When is it next one-fourth at its maximum?
The healing coils in a hair dryer are 0.800 cm in diameter, have a combined length of 1.00 m, and a total of 400 turns. (a) What is their total self-inductance assuming they act like a single solenoid? (b) How much energy is stored in them when 6.00 A flows? (c) What average emf opposes shutting them off if this is done in 5.00 ms (one-fourth at a cycle for 50 Hz AC)?
A 75-turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 radius in a 1.25 T field, starting with the plane of the coil parallel to the field. (a) What is the peak emf? (b) At what time is the peak emf first reached? (c) At what time is the emf first at its meet negative? (d) What is the period of the AC voltage output?
An 820-turn wire coil of resistance 24.0 is placed on lop of a 12 500-turn, 7.00-cm-long solenoid, as in Figure P20.57. Both coil and solenoid have cross-sectional area of 1.00 104 m2. (a) How long does it take the solenoid current to reach 0.632 times its maximum value? (b) Determine the average back emf caused by the self-inductance of the solenoid during this interval. The magnetic field produced by the solenoid at the location of the coil is one-half as strong as the field at the center of the solenoid. (c) Determine the average rate of change in magnetic flux through each turn of the coil during the stated interval. (d) Find the magnitude of the average induced current in the coil. Figure P20.57
When a magnetic field is first turned on, t1 flux through a 20-turn loop varies with time according to m=5.0t22.0t ,where m is in milliwebers, tis in seconds, and the loop is in the plane of the page with the unit normal pointing outward. (a) What is the emf induced in the loop as a function of time? What is the direction of the induced current at (b) t= 0, (c) 0.10, (d) 1.0, and (e) 2.0 s?
A rectangular conducting loop is placed near a long wire carrying a current I as shown in Figure OQS1.3. If I decreases in time, what can be said of the current induced in the loop? (a) The direction of the current depends on the size of the loop. (b) The current is clockwise. (c) The current is counterclockwise. (d) The current is zero. (e) Nothing can he said about the current in the loop without more information.
A 600-turn solenoid is 0.55 m long and 4.2 cm in diameter. Inside the solenoid, a small (1.1 cm × 1.4 cm), single-turn rectangular coil is fixed in place with its face perpendicular to the long axis of the solenoid. What is the mutual inductance of this system?
A large research solenoid has a self-inductance of 25.0 H. (a) What induced emf opposes shutting it off when 100 A of current through it is switched off in 80.0 ms? (b) How much energy is stored in the inductor at full current? (c) At what rate in waits must energy be dissipated to switch the current off in 80.0 ms? (d) In View of the answer to the last part, is it surprising that shutting it down this quickly is difficult?
A 120-V, series-wound dc motor draws 0.50 A from its power source when operating at full speed, and it draws 2.0 A when it starts. The resistance of the armature coils is 10 , (a) What is the resistance of the field coils? (b) What is tire back emf of the motor when it is running at full speed? (c) The motor operates at a different speed and draws 1.0 A from the source. What is the back emf in this case?
(a) A bicycle generator rotates at 1875 rad/s, producing an 18.0 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640 T field. How many turns are in the coil? (b) Is this number of turns of wire practical for a 1.00 by 3.00 cm coil?
(a) Calculate the self-inductance of a 50.0 cm long, 10.0 cm diameter solenoid having 1000 loops. (b) How much energy is stored in this inductor when 20.0 A of current flows through it? (c) How fast can it be turned off if the induced emf cannot exceed 3.00 V?
A solenoid 50 cm long is wound with 500 turns of wire. The cross-sectional area of the coil is 2.0 cm2. What is the self-inductance of the solenoid?