= 1 + 3y tanx

Q: Evaluate  ∫(sec x + 1)2 dx.

A:

Q: Solve for x if 0 ≤ x ≤ 360◦ tan x = −1

A:

Q: dy tan5 2x sec4 2x %3D

A: NOTE: Refresh your page if you can't see any equations. . use the formula  ................(1)

Q: Find tanC. 1 A 3 V3 2 O V3 3 2. 12

A: We will find tan C as following.

Q: 4x + y+1 = 2 tan 4x +y+1= 2 tam

A:

Q: Solve for x 3tan³x-3tan²x-tanx+1=0

A: The given trigonometric equation is: 3tan3x-3tan2x-tan x+1=0

Q: solve d = tan (x +y)

A: dydx=tan2(x+y)

Q: Y 15 12 9,

A:

Q: Differentiate implicitlyxy^2+tan(y^3)=10y

A: Given expression is:xy2 + tan(y3) =10y

Q: -3 y = (x* – 2x*) + tanx

A: Given,         y=x4-2x3-3+tanx

Q: ∫2π cosx dx 0

A:

Q: Evaluate

A: we have to evaluate:

Q: 6 tan²(x)dx

A:

Q: 1. y = tan 2x %3D

A: Since solve the first question for you. If you want any specific question to be solved then please…

Q: b) f(x) = tan (VInx) %3D

A: f(x)=tan^-1(sqrt(lnx))

Q: 1. y = (5x - 8)* + Sin(tan2x)

A: Note: Since you have asked multiple question, we will solve the first question for you. If you want…

Q: Find y': y = tan4(2x)

A: The given function is y=tan42x

Q: Find (tanx)

A: Given: ddx(tanx)

Q: Evaluate ∫sec3 x dx.

A:

Q: Differentiate.   y =  x tan -1(4x)

A: We have to differentiate, y=xtan-14x Here, given integral is in product form so according to product…

Q: calculate y" : y = tan(x2)

A:

Q: 3. y = xcos(2x) 4. y = tan tan (3x)

A: To find out the derivative of the function.

Q: Differentiate y= 2x tan(V2x (/25).

A:

Q: @ y = x tan 2x

A:

Q: Solve: dy +ysecx = tan x dx

A: The given differential equation is, dydx+ysecx=tanx The given linear equation is Linear Differential…

Q: Evaluate y” - y’-2y = sin2x

A: Using method of linear differential equation.

Q: Evaluate: ∫ sec6x tan3x dx

A:

Q: Evaluate:

A: Given integral is By using the following substitution we have

Q: Find ∫ tan5 x dx

A: To integrate: ∫tan5xdx.  Given integral can be written as: ∫tan5xdx=∫sin5xcos5xdx Let substitute…

Q: Find ∫sec3 x dx.

A: We have to find the integration: ∫sec3 x dx Assuming, I=∫sec3 x dx Rewriting the above integral,…

Q: Differentiate y = (tanx-1) /secx

A: we need to evaluate derivative of y = tan x - 1sec xthis can be done by using quotient rule. That…

Q: Evaluate 1 tan |2x| dx 100

A:

Q: 5. y= 3tan 2x + tan³2x

A:

Q: 1. y = 8cosx + 13 2. y = 2x³ + 2secx 3. y = 4 tan(2x)

A:

Q: Find : (a) y = (x³ + 5) tan 7x,

A:

Q: 11. y = x®tan³x

A:

Q: find (tanx)

A: The derivative of tanx, ddxtanx=ddxsinxcosx The derivative of tanx using the quotient rule,…

Q: y"'-2y"= tanx

A: We solve this by using the power series. We expect the solution to have a power series expansion…

Q: Evaluate  ∫ √(4 − x2) dx

A:

Q: Find y lnxy tan (X+9)

A:

Q: -1 tanx X 1+x?

A:

Q: Differentiate y = tan(2x).

A: The given function is y=tan(2x)

Q: TT sec (2x) tan(2x) dx T/3 8T

A:

Q: S(secx – tanx)²dx

A: I have stated the used formulas in the solution

Q: Calculate y". y = tan(x2)

A: First of all, consider the formula for the chain rule and the given function y. Then assume u and v…

Q: y = 3 tan 2x + tan³ 2x

A:

Q: 9. S(2 + tan² x)dx

A: We have to integrate each term with respect to x to get the final answer.

Q: y = sin (tan 3x) -1

A: Using derivative of composite functions.