1) An object has a velocity vo(t=0.0 s) = (1.00 m/s)i + (-1.00 m/s)j at time t = 0.00 s. The acceleration of the object is -> a (t) = (-6.00 m/s³)ti + (12.0 m/s4)t2j. If the object is located at ro(t) = (1.00 m)i + (-1.00 m)j at time t= 0.00 s., a) What is the velocity as a function of time? b) What is the velocity at time t= 0.00 s? c) what is the position of the object as a function of time? d) what is the position of the object at time t = 1.00 s? b)でe)-(1-3も3)msPt At- Osec

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 10P: An object moves along the x axis according to the equation x = 3.00t2 2.00t + 3.00, where x is in...
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I need help solving part D
1) An object has a velocity vo(t=0.0 s) = (1.00 m/s)i + (-1.00 m/s)j at time t= 0.00 s. The acceleration of the object is
a (t) = (-6.00 m/s³)ti + (12.0 m/s4)t2j. If the object is located at ro(t) = (1.00 m)i + (-1.00 m)j at time t = 0.00 s.,
a) What is the velocity as a function of time?
b) What is the velocity at time t= 0.00 s?
c) what is the position of the object as a function of time?
d) what is the position of the object at time t = 1.00 s?
b)ve)=(1-362)mrsit
At = Osec
えニ-G6+1262
%3D
GtT+12と
%3D
9.
+12
3.
2
Transcribed Image Text:1) An object has a velocity vo(t=0.0 s) = (1.00 m/s)i + (-1.00 m/s)j at time t= 0.00 s. The acceleration of the object is a (t) = (-6.00 m/s³)ti + (12.0 m/s4)t2j. If the object is located at ro(t) = (1.00 m)i + (-1.00 m)j at time t = 0.00 s., a) What is the velocity as a function of time? b) What is the velocity at time t= 0.00 s? c) what is the position of the object as a function of time? d) what is the position of the object at time t = 1.00 s? b)ve)=(1-362)mrsit At = Osec えニ-G6+1262 %3D GtT+12と %3D 9. +12 3. 2
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