The position of a particle is T(t)= (2.0r21-3.0t /)m.What is the magnitude of the acceleration (in m/s) after 1.0 s2?

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Description: The position of a particle is T(t)= (2.0r21-3.0t /)m.What is the magnitude of the acceleration (in m/s) after 1.0 s2?

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The position of a particle is 7(t) = (2.0t21-3.0t Jm.What is the magnitude of the acceleration (in m/s) after 1.0 s?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 11P: A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in...

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The position of a particle is T(t)
= (2.0r21-3.0t /)m.What is the magnitude of the acceleration (in m/s) after 1.0 s2
?

Expert Solution

Answer

Acceleration is constant which means that acceleration is not the function of time (it will not change with respect to time)

Therefore, the magnitude of acceleration after 1.0 s is 4 m/s²and the direction is x-axis

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