1: A(W12x53) section has connected by two rows of (1-inch-diameter bolts) in each flange and in web as shown in Figure (1). Determine the maximum tensile strength by using LRFD method and A992 steel material, then check the adquency of this section if the applied service dead load is 250 kips, live load = 400 kips.
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- The plate shown is attached by using three M12x2 grade 8.8 bolts. Which screw is subjected to the largest stress? What safe load ( static) F can be supported by the screw for n=1.5.Determine the Net Area for the following Plate Section consider all possible Cases. The Plate thickness is 1-in. and the bolts' diameter is 7/8-in. s = 6.0 " g = 2.0 "A 1 ⁄2 × 5-inch plate of A588 steel is used as a tension member. It is connected to a gusset plate with four 5 ⁄8-inch-diameter bolts as shown in Figure 1. Assume that the effective net area Ae equals the actual net area An. (a) Calculate the design strength for LRFD? (b) Calculate the allowable strength for ASD?
- 0.1: An MC9x23.9 is connected with 3 /4-inch diameter bolts as shown below. A572 Grade 50 steel is used. Determine the design strength for the section.an angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kNThe unbraced column length of Round HSS 18 x0.5 in A500 Grade C (Fy = 50 ksi) is 30 ft.Determine the design compressive strength of the column using the equations in Chapter E inPart 16 of the AISC Manual. Confirm your answer using the AISC Manual Table 4-5 (pages 4-84,New AISCM) and (pages 4-84, New AISCM). The column has pin supports at both ends ( i.e Kx= Ky = 1.0) columns. Lx = Ly = 30 ft
- check the adequacy of W10 x 60 section to resist a service tensile load that induce the following forces: PD = 180k, E = 147.1 k and PL = 205k. The member length is 30ft and assumed to have two lines of holes in the web with 3" gauge. Assume there are four bolts in each line at 3 in c/c. All holes for 7/8 - in diameter bolts. The section must satisfy the slenderness effect.The given angle bar L125x75x12mm with Ag = 2269 sq. mm is connected to a gusset plate using 20 mm diameter bolts as shown in the figure. Using A36 stell with Fy = 248 MPa and Fu = 400 MPa, determine the nominal tensile strength based on gross yielding (kN), determine the effective net area of the tension member if the shear lag factor is 0.80, determine the ultimate tensile strength (kN) based on tensile rupture.A single-angle tension member 175 mm x 100 mm x 18 mm haw two gage lines in its long leg and one in the short leg for 16 mm bolts arranged as shown. Area of the angular section is 4961 mm^2. Use A36 steel Fy = 248 MPa and Fu = 400 MPa. Standard nominal hole diameter for 16 mm bolt = 17 mm. Determine the net area of the angular section. Determine the allowable tension strength of the angular section based on the gross area. Determine the allowable tensile strength of the angular section based on the effective net area. Reduction factor U = 0.75
- A single angle tension member, L 4 x 4 x 3/8 in. made from A36 steel is connected to a gusset plate with 5/8 in. diameter bolts, as shown in Figure below. The service loads are 35 kips dead load and 15 kips live load. Determine the adequacy of this member using AISC specification. Assume that the effective net area is 85% of the computed net area.3.6-5 Use load and resistance factor design and select an American StandardChannel shape to resist a factored tensile load of 180 kips. The length is15 ft, and there will be two lines of 7⁄8-in. diameter bolts in the web, asshown in Figure P3.6-5. Estimate the shear lag factor U to be 0.85. (In apractical design, once the member and bolt layout are selected, the valueof U could be computed and the member design could be revised if necessary.)Use A36 steel.5. a bolted lap joint shown in the figure below. The bolts are 20m in diameter in 23 mm holes. The plates are 12m thick X350 Allowable stress of Plates: Tenaion in gross area0.60Fy Tension in net area0.50 Fu Shear on Net Area 0.30Fu Yield Strength of plate, Fy 248 Npa Ultinate tensile strength of Plate. Fu400 Mpa x, Find the safe load P based on a- Gross area yielding b. net area rapture c. block shear 2 of 3