Question
Asked Jun 11, 2019
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In Figure (a) particles 1 and 2 have charge 38.0 μC each and are held at separation distance d = 4.70 m.

(a) What is the magnitude of the electrostatic force on particle 1 due to particle 2? In Figure (b), particle 3 of charge 38.0 μC is positioned so as to complete an equilateral triangle.

(b) What is the magnitude of the net electrostatic force on particle 1 due to particles 2 and 3?

 

1
d
3
.d
2.
(b)
(a)
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1 d 3 .d 2. (b) (a)

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Expert Answer

Step 1

Given,

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The magnitude of charges, = |g|= 38.0 x 10 C Separation between charges (1 and 2), d 4.70m

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Step 2

From Coulomb’s law, magnitude of force between two charge,

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F =kl|g k - d2 where amagnitude of first charge g,=magnitude of second charge d separation between charge N m2 k(Coulomb's constant) = 9 x 10' c

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Step 3

Part (a)

Since, both charges 1 and 2 have equal sign, the...

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(38.0 x 10 C)(38.0x10 C 9x109 N m C2 (4.70m) =0.588 N

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