(1 + (dy/dx)2)3/2 |d²y/dx²| (1 + (dx/dy)?)3/2 r = |d?x/dy?| r = or The osculating circle (solid red) at a point is the tangent circle that best fits the curve.

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.1PS
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Explore the radius of curvature of curves. There can be many circles (hat are tangent to a curve at a particular point, but there is one that provides a "best fit" (Figure). This circle is called an osculating circle of the curve. We define it formally in Section 13.4. The radius of the osculating circle is called the radius of curvature of the curve and can be computed using either of the formulas: Consider the ellipse x 2 + 4 y2 = 16.
(a) Compute the radius of curvature in terms of x and y.
(b) Compute the radius of curvature at (4, 0), (2, -J3), and (0, 2). Sketch the ellipse, plot these three points, and label them with the corresponding radius of curvature.

(1 + (dy/dx)2)3/2
|d²y/dx²|
(1 + (dx/dy)?)3/2
r =
|d?x/dy?|
r =
or
The osculating circle (solid red) at a point is the tangent
circle that best fits the curve.
Transcribed Image Text:(1 + (dy/dx)2)3/2 |d²y/dx²| (1 + (dx/dy)?)3/2 r = |d?x/dy?| r = or The osculating circle (solid red) at a point is the tangent circle that best fits the curve.
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