1 mol super cooled liquid water transformed to solid ice at -10 oC under  1 atm pressure. a) Calculate entropy change of the system, surrounding and universe. (temperature of the environment is -10 °C) b) Make some comments on entropy changes from the obtained data Please use the following data for water : Melting entalpy of ice (ΔHmelting) at 0°C and 1 bar is 6020 J mol-1.

Gaseous SO2Cl2 reacts with liquid water to form hydrogen chloride gas and liquid sulfuric acid. Using data tabulated in Appendix G of your text, calculate the enthalpy change, in units of kJ/mol, for the formation of 2 mol of liquid sulfuric acid.

E The Carnot cycle, which is a particular example of a thermodynamic cycle, allows determining the efficiency of a "heat-to-work" engine. Clausius used this to find the macroscopic definition of entropy as the heat change of the system at a particular temperature. Th and T are the high and low qh and q for the heats transferred at these temperatures. When plotted in a T-S temperatures and representation, entropy only changes in the processes (steps) where heat is added or removed. However, when plotting the Carnot cycle in the P-V representation it is clear that work is done (on or by) the system in each of the 4 processes of the cycle. a) Give the names of the 2 processes of the Carnot cycle (an engine) in which the surroundings do work on the system. Indicate the condition(s) of the walls for these processes. b) Consider the microscopic, i.e., Boltzmann's, definition of entropy for an ideal gas. Briefly discuss what needs to be satisfied so that there is no change of entropy during a…

Mark the correct statements. (Select all that apply.) O [The reaction 2H20(g) → 2H2(g) + O2(g) is expected to have a positive value of ASº.] O [If a sample of pure ozone changed to oxygen at constant T and P, the entropy of the sample would decrease.] O [For the process H20(1) → H20(s) occurring at 0°C and 1 atm, the sign of AS is negative.] O [The value of AS for the process CHC13(1) – CHC13(g) is negative.] O [The reaction CH4(g) + 202(g) → CO2(g) + 2H2O(g) has a negative value of ASsurr-]

Consider the reaction: 6CO2(g) + 6H₂O(l) → C6H12O6 + 602 (9) Using standard thermodynamic data at 298 K, calculate the entropy change for the surroundings when 1.87 moles of CO₂ (g) react at standard conditions. AS⁰ Substance AH (kJ/mol) CO₂ (g) -393.5 H₂O(1) -285.8 C6H12O6 -1275.0 O₂(g) 0.0 surroundings J/K

A chem.. ngineer is studying the two reactions shown in the table below. In each case, he fills a reaction vessel with some mixture of the reactants and products at a constant temperature of 52.0 °C and constant total pressure. Then, he measures the reaction enthalpy AH and reaction entropy AS of the first reaction, and the reaction enthalpy AH and reaction free energy AG of the second reaction. The results of his measurements are shown in the table. Complete the table. That is, calculate AG for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether, under the conditions the engineer has set up, the reaction is spontaneous, the reverse reaction is spontaneous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium. AH = 181. kJ J AS = 557. K N, (g) + 0, (g) → 2NO (g) AG = N, (g) + 0,(8) kJ Which is spontaneous? this reaction the reverse reaction neither ΔΗ - - 1353. kJ J AS = K 2CH,OH (g) + 30,(g)…

In a process, 3 mol of an ideal gas (Cp= 2.5 R) and 1 atm change to 125°C and 5 atm. Calculate the entropy change from process to system.

The vaporisation of a certain element at 25.0 oC has the following enthalpy and entropy values: Hvap = 1.00 kJ mol-1     and Svap = 156 J K-1 mol-1. What is the total entropy change (Stot) for the vaporisation of this element, in J K-1mol-1?

M Preq 3 Consider the reaction 00 E D 4HCI(g) + O₂(g) 2H₂O(g) + 2Cl₂(8) for which AH° = -114.4 kJ and AS° = -128.9 J/K at 298.15 K. J/K (1) Calculate the entropy change of the UNIVERSE when 1.775 moles of HCI(g) react under standard conditions at 298.15 K. ASuniverse (2) Is this reaction reactant or product favored under standard conditions? Submit Answer (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant favored'. 4 000 000 R F DO LO V % 5 [Review Topics] [References] Use the References to access important values if needed for this question. T Retry Entire Group 8 more group attempts remaining Cengage Learning Cengage Technical Support G 6 B Y H & 7 N U 1 * 8 J M 9 K बैं O < L P Previous Email Instructor Save and Exit { + 11 Next ? } ]

Please answer the following in the attached.