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complete the reactions given below
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- Choose the one has the highest priority, and the one has the lowest. (Please show why) -CHO -COOH -COCH3 -CONH2What reagent is necessary to complete the reaction? CH3-CH2-CH-C-OH ? CHỊCH,CH C-0- Na* CH3 CH3 NaO O NaCl O Na O NaOH + H₂ORank the following groups in order of decreasing priority. −COOH, −CH2OH, −H, −CHO
- hi! i need answers on letters d to f. The instructions says give the IUPAC name of each compound. Thank u!Which set of answers is organized in orderfrom highest to lowest priority?A. –CH2NH2 > –CN > –COOH > –NH2B. –COOH > –CN > –CH2NH2 > –NH2C. –NH2 > –CN > –CH2NH2 > –COOHD. –NH2 > –COOH > –CN > –CH2NH2E. –CN > –NH2 > –CH2NH2 > –COOHRank the following groups in order of decreasing priority. −C≡CH, −CH(CH3)2, −CH2CH3, −CH=CH2
- Cyclohexene plus 1) Hg(OAc)2, H2O; 2) NaBH4; yields __________. HO2CCH2CH2CH2CH2CO2H a cyclic diketone cyclohexyne cyclohexanol OHCCH2CH2CH2CH2CHO4-Methylphenol, CH3C6H4OH (pKa 10.26), is only slightly soluble in water, but its sodium salt, CH3C6H4O- Na+, is quite soluble in water. In which solution(s) will 4-methylphenol dissolve? Q.) Aqueous NaOHOChem help with IUPAC names involving Ph and Bn The phenyl group (Ph-R, C6H5-R) can be formed by removing a hydrogen from benzene and attaching a substituent to where the hydrogen was removed. The benzyl group (abbv. Bn), similar to the phenyl group, is formed by manipulating the benzene ring. In the case of the benzyl group, it is formed by taking the phenyl group and adding a CH2 group to where the hydrogen was removed. Its molecular fragment can be written as C6H5CH2-R, PhCH2-R, or Bn-R. Please provide the IUPAC name for the following: (Ph)2CHC(CH3)2CC(CH2)3CH(Bn)CHO