1) To loosen a pipe fitting, a plumber slips a piece of scrap pipe (a “cheater") over his wrench handle. He stands on the end of the cheater, applying his 900-N weight at a point 0.80 m from the center of the fitting (figure on the right). The wrench handle and cheater make an angle of 19- with the horizontal. Find the magnitude and direction of the torque he applies about the center of the fitting. Draw the free-body diagram. 0.50m F= 900 N 19

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
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Chapter10: Fixed-axis Rotation
Section: Chapter Questions
Problem 74P: When tightening a bolt, you push perpendicularly on a wrench with a force of 165 N at a distance of...
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1) To loosen a pipe fitting, a plumber slips a piece of scrap pipe (a “cheater")
over his wrench handle. He stands on the end of the cheater, applying
his 900-N weight at a point 0.80 m from the center of the fitting (figure
on the right). The wrench handle and cheater make an angle of 19- with
the horizontal. Find the magnitude and direction of the torque he
applies about the center of the fitting. Draw the free-body diagram.
0.80 m
F = 900 N
19
Transcribed Image Text:1) To loosen a pipe fitting, a plumber slips a piece of scrap pipe (a “cheater") over his wrench handle. He stands on the end of the cheater, applying his 900-N weight at a point 0.80 m from the center of the fitting (figure on the right). The wrench handle and cheater make an angle of 19- with the horizontal. Find the magnitude and direction of the torque he applies about the center of the fitting. Draw the free-body diagram. 0.80 m F = 900 N 19
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