(1) {w € (a, b)*: every a in w is immediately preceded and followed by b} Testing strings: €, a, b, aa, ab, ba, bb, bab, aba, bbb, abab, baab, baba, babab The accepted strings are: U U U U U U U € a aa ab ba bb bab aba bbb abab baab baba babab
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- PYTHON CODE: In order to beat AlphaZero, Grandmaster Hikaru is improving her chess calculation skills.Today, Hikaru took a big chessboard with N rows (numbered 1 through N) and N columns (numbered 1 through N). Let's denote the square in row r and column c of the chessboard by (r,c). Hikaru wants to place some rooks on the chessboard in such a way that the following conditions are satisfied:• Each square of the board contains at most one rook.• There are no four rooks forming a rectangle. Formally, there should not be any four valid integers r1, c1, r2, c2 (≠r2,c1≠c2) such that there are rooks on squares (r1,c1), (r1,c2 (r2,c1)and (r2,c2).• The number of rooks is at least 8N.Help Hikaru find a possible distribution of rooks. If there are multiple solutions, you may find any one. It is guaranteed that under the given constraints, a solution always exists.InputThe first line of the input contains a single integer T denoting the number of test cases. The first and only line of each test…Q#2 Write a recursive function zeroCount ( int a[ ], int s, int e) that receives an array of integers a [], a start index s, and an end index e. The function should return the number of zeros in that array between s and e. int zeroCount ( int a[ ], int s, int e); Trace your function given the following array and function call. Draw your steps. int a[ ] = {1, 0, 0, 5}; int zeros = zeroCount(a, 0, 3); language c++Q4. Recursion Find how many possible combinations that a number can be decomposed into the multiple of integers (smaller than the number itself) by a recursion function.Suppose we have a positive number Y as input, and it need to be decomposed into the multiple of several integers, Yi, where each Yi, is smaller than Y(e.g., Y=Y1∗Y2∗ Y3∗...∗Yn). In addition, these decomposed integers can only be arranged in an ascending order (Y1
- Let’s assume M is a set defined as M ⊆ Z^+ × Z^+. Assume that M is defined using the concept of recursion taught in class as: i) (1, 2) ∈ M, ii) If (x, y) ∈ M, then (3x − y, 2x) ∈ M. Perform 5 recursive steps to obtain the updated M.TROUBLESHOOT my PYTHON code, please :) The code of a sequential search function is shown on textbook page 60. In fact, if the list is already sorted, the search can halt when the target is less than a given element in the list. For example, given my_list = [2, 5, 7, 9, 14, 27], if the search target is 6, the search can halt when it reaches 7 because it is impossible for 6 to exist after 7. Define a function linearSearchSorted, which is used to search a sorted list. This function displays the position of the target item if found, or 'Target not found' otherwise. It also displays the elements it has visited. To test your function, search for these targets in the list [2, 5, 7, 9, 14, 27]: 2, 6, 14, 27 and 28. Expected output: List: [2, 5, 7, 9, 14, 27] Search target: 2 Elements visited: 2 Target found at position 0 Search target: 6 Elements visited: 2 5 7 Target not found Search target: 14 Elements visited: 2 5 7 9 14 Target found at position 4 Search target: 27 Elements visited: 2…(C Language) The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, for example: 0, 1, 1, 2, 3, 5, 8, 13. Complete the Fibonacci() function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1.
- Programming Practice Problem in C (Arrays and Strings): Implement substringList() that will produce the collection of words from the 1D array B that has substrings equivalent to the string key. The resulting collection should be stored in array C and this should contain only the unique set of words. The function returns the resulting total number of elements in array C. For your reference, a substring is a contiguous sequence of characters within a string. As an example, the strings “app”, “ppl”, “apple”, and “e” are among the substrings from the string “apple”. But, strings “ale” are “elppa” are not substrings from string “apple”. Suppose B contains the following, with nElemB = 7: B[] = { "it's", "today", "now", "or", "forever", "today", "ACT"} Referring to the contents of array B above, suppose the following test cases and supposed contents of array C by the end of the function substringList(): key = "or" --> C[] = {"or", "forever"} --> function returns 2 key = "at" -->…Python code Here are n posts at particular directions on a plane. It is ensured that no three fence posts lie on a similar line. There are a limitless number of cows on the plane, one at each point with whole number directions. Gregor is an individual from the Illuminati, and needs to construct a three-sided fence, interfacing 3 unmistakable existing wall posts. A cow stringently inside the fence is supposed to be encased. In case there are an odd number of encased cows and the space of the fence is a whole number, the fence is supposed to be intriguing. Track down the quantity of intriguing wall. Information : The primary line contains the whole number n (3≤n≤6000), the quantity of fence posts which Gregor can decide to shape the vertices of a fence. Every one of the following n line contains two whole numbers x and y (0≤x,y≤107, x and y are even), where (x,y) is the arrange of a fence post. All fence posts lie at unmistakable directions. No three fence posts are on a similar…Code in C. Solve the code below. write a function that receives a vector of integers already sorted in ascending order, an integer n represents the number of elements in this vector, and an integer b. Implement the sequential search algorithm to look for the integer b in the vector. The binary search works as follows: you must look for the element in the position exactly in the half of the vector, if for the searched it returns the number of tests done so far, if not for the searched, calculate the midpoint of the half of the vector after assess whether the searched value is greater or less than the value at the middle position. Not finding the value searched, the function must return 0. The name of the function will be called "busca_bin". int busca_bin (int vetor [ ], int n, int b){ #include <stdio.h> int busca_bin(int vetor[] , int n , int a) { int s1 = 0; int s2 = n-1; int pass = 0; int s3; while(s1<s2) { s3 = (s1+s2)/2; pass++;…
- Code in C. Solve the code below. write a function that receives a vector of integers already sorted in ascending order, an integer n represents the number of elements in this vector, and an integer b. Implement the sequential search algorithm to look for the integer b in the vector. The binary search works as follows: you must look for the element in the position exactly in the half of the vector, if for the searched it returns the number of tests done so far, if not for the searched, calculate the midpoint of the half of the vector after assess whether the searched value is greater or less than the value at the middle position. Not finding the value searched, the function must return 0. The name of the function will be called "busca_bin". int busca_bin (int vetor [ ], int n, int b){// your code} My code #include <stdio.h> int busca_bin(int vetor[] , int n , int a) { int s1 = 0; int s2 = n-1; int pass = 0; int s3; while(s1<s2) {…5. Construct a function C(V) that counts the number of basic operations for the following algorithm. Then place the algorithm in a time efficiency class. State any assumptions you make. public static ArrayList topologicalSort(Graph dag) { Queue q = new LinkedList(); ArrayList sortOrder = new ArrayList(); int[] inEdgeCounts = new int[dag.size()]; for(int i = 0; i < inEdgeCounts.length; i++) { inEdgeCounts[i] = 0; } for(int i = 0; i < inEdgeCounts.length; i++) { dag.getAdjList(i).stream().forEach((x) -> inEdgeCounts[x]++); } // Identify sources for(int i = 0; i < inEdgeCounts.length; i++) { if(inEdgeCounts[i] == 0) { q.add(i); } } while(!q.isEmpty()) { int currVertex = q.remove(); sortOrder.add(currVertex); ArrayList adjList = dag.getAdjList(currVertex); // Remove edges for this node for(Integer adjVertex:…Recursion and loops. Provide both recurrent and loop based implementation of the function count( e, L ) that returns the number of es in L, where L is a list. Also consider cases when L is an empty list. Create test cases and run driver, show how function runs in spyder (py file) or ipynb file. Submit code as a py or html or pdf files with screenshots of the runs.