are 300 W,14-17 kWmechanicalof the motor withW (ii)90%)1. A 3-phase, 6-pole, 50 Hz induction motor develops 3.68find the stator input.kW at 950 r.p.m. If the stator lossestotal 1 kWand the2. The power input to a 3-phase induction motor is 40 kW. The stator losseslosses are 1-6 kW. Determine (1) shaft power (ii) rotor Cu loss and (iii) efficiencya slip of 3-5%.1(0) 36 kW (i) 445plL2

Since both question are not interlinked as per the guidelines of Bartleby we supposed to answer…

1. A 3-phase, 6-pole, 50 Hz induction motor develops 3-68 kW at 950 r.p.m. If the stator losses are 300 W, find the stator input. 14-17 kW 2. The power input to a 3-phase induction motor is 40 kW. The stator losses total 1 kW and the mechanical losses are 1-6 kW. Determine (1) shaft power (ii) rotor Cu loss and (iii) efficiency a slip of 3-5%. of the motor with 1(0) 36 kW (i) 445 W (ii) 90%) pl 2

1. A 3-phase, 6-pole, 50 Hz induction motor develops 3-68 kW at 950 r.p.m. If the stator losses are 300 W, find the stator input. 14-17 kW 2. The power input to a 3-phase induction motor is 40 kW. The stator losses total 1 kW and the mechanical losses are 1-6 kW. Determine (1) shaft power (ii) rotor Cu loss and (iii) efficiency a slip of 3-5%. of the motor with 1(0) 36 kW (i) 445 W (ii) 90%) pl 2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

The no-load and locked-rotor test results of a three-phase 10 HP, 220 V, 60 Hz, 6 poles star connected induction motor are; The no-load test: VNL=220 V, PNL=340 W, INL=6.2 A The locked-rotor test: VSC=54 V, PSC =430 W, ISC =15.2 A The voltage across the stator windings is 2 V when nominal DC current flows through it. Coefficient for DC resistance is 1,25. a) Calculate the equivalent circuit parameters and draw the complete single-phase equivalent circuit of the induction motor. b) Calculate efficiency of the motor for s=0.06 by using the approximate equivalent circuit (RFe core resistance is not ignored). c) Shaft torque for s=0,06 d) Slip value at the maximum (breakdown) torque, e) Maximum (breakdown) torque of the induction motor. f) Speed of the motor at maximum torque point. g) Rotor frequency at maximum torque.
A four-pole, single-phase, 120 V, 60 Hz induction motor gave the following standstill impedances when tested at rated frequency:Main winding : Zm =1.5+j4 ohmsAuxiliary winding : Za =3+j6 ohmsa) Determine the value of external resistance to be inserted in series with the auxiliary winding to obtain maximum starting torque as a resistor split-phase motor.b) Determine the value of the capacitor to be inserted in series with the auxiliary winding to obtain maximum starting torque as a capacitor-start motor.c) Determine the value of the capacitor to be inserted in series with the auxiliary winding to obtain maximum starting torque per ampere of the starting current as a capacitor-start motor.d) Compare the starting torques and starting currents in parts (a), (b), and (c) expressed as per unit of the starting torque without any external element in the auxiliary circuit, when operated at 120V, 60Hz.
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A 110-V, 50-Hz single phase induction motor (split -phase) has the following constants for the main and auxiliary windings: Main winding, Zm (1.2 +j 25) ohm and auxiliary winding, Z,= (12+j 5) ohm. Determine (i) total current and power factor currents at time of starting, and (ii) phase angle between the main winding current and starting winding current.
A single-phase, 120 V, 60 Hz, 1/2 hp, 1740 rpm split-phase fan motor gave the following testresults:V I PNo load test 120 4 110Standstill test (main winding) 41 5.8 115Standstill test (auxiliary winding) 38 7 200Main winding resistance = 1.85 Ω.a) Obtain an equivalent circuit for the motor for running conditions.b) Determine the no-load rotational loss.c) Determine the efficiency at the rated speed.
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23. As load is increased from no load to full load on a 3-phase squirrel-cage induction motor, what happens to the ...D) stator current of the motor?a) increases b) decreases c) remains the same d) none of the aboveE) power factor of the motor?a)improves, b)get poorer, c)remains the same, d)none of aboveF) efficiency of the motor?a)increases b)decreases c) remains the same d) none
The standstill reactance of each phase of a three-phase induction motor with star-connected rotor are 0.06 ohms and 0.4 ohms respectively. The full-load slip is 4%. Calculate the resistance per phase of a star-connected rheostat, which when connected to the rotor, will give a pull out torque at one half of the full-load speed. What is then the power factor?
PLEASE ONLY ANSWER THE D E F G PARTS PLEASE ANWSER AS SOON AS POSSIBLE. Thanks in advance. The no-load and locked-rotor test results of a three-phase 10 HP, 220 V, 60 Hz, 6 poles star connected induction motor are;The no-load test:VNL=220 V, PNL=340 W, INL=6.2 AThe locked-rotor test:VSC=54 V, PSC =430 W, ISC =15.2 AThe voltage across the stator windings is 2 V when nominal DC current flows through it. Coefficient for DC resistance is 1,25.a) Calculate the equivalent circuit parameters and draw the complete single-phase equivalent circuit of the induction motor.b) Calculate efficiency of the motor for s=0.06 by using the approximate equivalent circuit (RFe core resistance is not ignored).c) Shaft torque for s=0,06 d) Slip value at the maximum (breakdown) torque,e) Maximum (breakdown) torque of the induction motor.f) Speed of the motor at maximum torque point.g) Rotor frequency at maximum torque.