Some possibly useful numbers= 8.99 x 10° N m2/C2 €0 = 8.85 x 10-12C²/Nm24TEO%3D= 10-7Tm/Ae = 1.6 x 1019 Cme = 9.11 x 10-31kgmp = 1.67 x 10-27kg%3DleV = 1.6 x 10-19 J 1. A 500.0 Ohm resistor is connected to a 1.5 V battery.(a) Calculate the current through this resistor.(b) Calculate the power dissipated in the resistor.IS

Given-Resistor=500 ohmVoltage=1.5VoltCurrent-Flow of electron in a conductor is called…

Answered: 1. A 500.0 Ohm resistor is connected to…

1. A 500.0 Ohm resistor is connected to a 1.5 V battery. (a) Calculate the current through this resistor. (b) Calculate the power dissipated in the resistor.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 1.6OQ

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Concept explainers

Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting material, its cross-sectional area, resistivity, and temperature.

Question

Some possibly useful numbers
= 8.99 x 10° N m2/C2 €0 = 8.85 x 10-12C²/Nm2
4TEO
%3D
= 10-7Tm/A
e = 1.6 x 1019 C
me = 9.11 x 10-31kg
mp = 1.67 x 10-27kg
%3D
leV = 1.6 x 10-19 J

1. A 500.0 Ohm resistor is connected to a 1.5 V battery.
(a) Calculate the current through this resistor.
(b) Calculate the power dissipated in the resistor.
IS

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