1. A current of 3.6 A transfers a charge of 375 mC (375 x 103). How long would this take?

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Q: 12 V 20 2 A E 10 V 50

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Q: 1. In the following figure: R = 3 kN X; = 2 kN Xc = 1 kN %3D + VC + VR VL e = 6 sin(314t + 60°)

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Q: An inductor has the folowing characteristics: Iron core, diameter = 5cm 879 turns Length = 16cm Give...

A: The answer is 9.436 mH  or 9.436*10^(-3) H   The detailed solution is given in below image 

Q: +8V oVo て1 םאר4

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Q: Tdeal diodes Dz 1-5kr 3. 9. Determine Vo (-) ayde. For (+) and Vi Vo b. Draw Vo. 2.sv+ + 1av

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A: Power = current ^2 * resistance P= I^2* R  Power is measured in watts

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Q: 1. a) Use the mesh-current method to write a complete set of independent equations that could be use...

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Q: A 3-phase 3-wire, 415 V supplies a balanced load of 20 A at power factor 0.8 lngging. Two wattmeters...

A: The solution is given below 

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Q: 22052 本。 V2 12002

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.