1. A pair of genes AB are completely linked together, so they are tightly linked. Give the genotypic ratio of the cross between a heterozygous and recessive parents. 2. Why is coefficient of coincidence a basis for strength of linkage?
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1. A pair of genes AB are completely linked together, so they are tightly linked. Give
the genotypic ratio of the cross between a heterozygous and recessive parents.
2. Why is coefficient of coincidence a basis for strength of linkage?
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- 2. If an individual with the genotype Yy Ww Pp ee Bb is crossed with another individual with the same genotype, what proportion of offspring will be homozygous recessive at all genes? Answers: 1/1024 5/128 1/256 3/16 1/16 3. If an individual with genotype Yy Ww Pp ee Bb is crossed with an individual with the same genotype, what proportion of offspring will have the dominant phenotype for the four heterozygous loci? answers: 81/256 81/128 27/256 3/16The coat color of black bears depends on a gene with two alleles. Allele B is dominant and confers black coat, whereas allele b is recessive and homozygous bears have white coats (albino black bears, I know it sounds weird but it is true). As we know from genetics each bear has two alleles and the coat colors are as follows: BB-black; Bb-black; bb-white. A researcher obtained the following data for the genotypes (BB, Bb or bb) of black bears: Genotype Number of bears BB 42 Bb 24 bb 21 You are performing the following hypothesis test: H0: The genotypes of the bears follow a binomial distribution, with a probability of receiving the b allele equal to the observed proportion of the b allele in the population. HA: The genotypes of the bears do not follow a binomial distribution Q1 What is the fraction of b alleles in the population? Remember each bear has two alleles! Q2 What is the expected frequency of bears with genotype BB, Bb, and bb? Give the absolute expected…The coat color of black bears depends on a gene with two alleles. Allele B is dominant and confers black coat, whereas allele b is recessive and homozygous bears have white coats (albino black bears, I know it sounds weird but it is true). As we know from genetics each bear has two alleles and the coat colors are as follows: BB-black; Bb-black; bb-white. A researcher obtained the following data for the genotypes (BB, Bb or bb) of black bears: Genotype Number of bears BB 42 Bb 24 bb 21 You are performing the following hypothesis test: H0: The genotypes of the bears follow a binomial distribution, with a probability of receiving the b allele equal to the observed proportion of the b allele in the population. HA: The genotypes of the bears do not follow a binomial distribution What is the expected frequency of bears with genotype BB, Bb, and bb? Give the absolute expected frequency (number of bears) not the fraction/proportion of BB bears
- Suppose we randomly sample 50 diabetics from among Irvine residents for a research study, and then for each diabetic we sample one non-diabetic Irvine resident with the same sex, age (within 5 years), and race. Among these participants there are 21 pairs for which the diabetic reports low SES and the non-diabetic reports high SES, 9 pairs for which both report low SES, 2 pairs for which both report high SES, and 18 pairs for which the diabetic reports high SES and the non-diabetic reports low SES. Test the null hypothesis that there is no association between SES and diabetes in Irvine.An aircraft emergency locator transmitter (ELT) is a device designed to transmit a signal in the case of a crash. Company A makes 80% of the ELTs, Company B makes 15% of them and Company C makes the other 5%. The ELTs made by Company A have a 7.8% rate of defects, the Company B ELTs have a 6.3% rate of defects and the Company C ELTs have 6.4% rate of defects. If a randomly selected ELT is tested and found to be defective, find is the probability that it was made by Company A? Give your answer to three decimal places.A particular article reported the accompanying data on phenotypes resulting from crossing tall cut-leaf tomatoes with dwarf potato-leaf tomatoes. There are four possible phenotypes: (1) tall cut-leaf, (2) tall potato-leaf, (3) dwarf cut-leaf, and (4) dwarf potato-leaf. Mendel's laws of inheritance imply that ?1 = 9/16, ?2 = 3/16, ?3 = 3/16, and ?4 = 1/16. Are the data from this experiment consistent with Mendel's laws? Use a 0.01 significance level. (Use 2 decimal places.) Phenotype 1 2 3 4 Frequency 926 287 294 103 ?2 = P-value interval A p < 0.0010 B .001 ≤ p < 0.01 C 0.01 ≤ p < 0.05 D 0.05 ≤ p < 0.10 E p ≥ 0.10
- A researcher is conducting an experimental study on the effect of aspirin on heart attack risk. In order to assign who will receive aspirin and who will receive a placebo, she first divides her study into three age groups (18-29, 30-49, and 50 or older). She then randomly assigns individuals within these age groups to either receive aspirin or the placebo. This is an example of a cluster ?In Colorado, there is a large group of deer that spend their summer months in a region on one side of a highway and survive the winter months in a lower region on the other side. To determine if the highway has disturbed deer migration to the winter feeding area, the following data were gathered on a random sample of 10 wilderness districts in the winter feeding area. Row B represents the average January deer count for a 5-year period before the highway was built, and row A represents the average January deer count for a 5-year period after the highway was built. The highway department claims that the January population has not changed. Test this claim against the claim that the January population has dropped. Use a 5% level of significance. Units used in the table are hundreds of deer. (Let d = B − A.) Wilderness District 1 2 3 4 5 6 7 8 9 10 B: Before highway 10.1 7.2 12.9 5.6 17.4 9.9 20.5 16.2 18.9 11.6 A: After highway 9.3 8.4 10.2 4.1 4.0 7.1 15.2 8.3 12.2 7.3 What…A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on the same 12 cars, chosen at random. In particular, each car has one tire of each brand on its front wheels, with half of the cars chosen at random to have Brand 1 on the left front wheel, and the rest to have Brand 2 there. After all of the cars are driven over the standard test course for 20,000 miles, the amount of tread wear (in inches) is recorded, as shown in the table below. Car 1 2 3 4 5 6 7 8 9 10 11 12 Brand 1 0.64 0.53 0.32 0.61 0.59 0.64 0.34 0.58 0.53 0.43 0.38 0.34 Brand 2 0.47 0.48 0.31 0.37 0.56 0.37 0.30 0.57 0.49 0.41 0.50 0.17 Difference(Brand 1 - Brand 2) 0.17…
- Suppose that in a study of 35 million HPV shots examined, the shots were followed in time by 14,000 serious ailments and 32 confirmed deaths. However, suppose in examining a randomly selected control group of 35 million non-vaccinated people of the same age at a particular time A, 0.0413% developed a serious ailment soon after time A, and 0.000089% died soon after time A. What does the comparison of two groups tell us? What are the percentages in the vaccinated group (serious ailments and confirmed deaths), and how to they compare to the nonvaccinated group? Hint: compute the percentages for serious ailments (14,000/35,000,000) and confirmed deaths (32/35,000,000) for the vaccinated group. Compare with the control group. Notice % above. (0,0413% and 0.000089%) Answer here. What can we conclude with high probability, if this comparison between vaccinated and non-vaccinated groups was done many times with the same basic results? Answer here. Can we absolutely rule out that the…A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on the same random sample of 12 cars. In particular, each car has one tire of each brand on its front wheels, with half of the cars chosen at random to have Brand 1 on the left front wheel, and the rest to have Brand 2 there. After all of the cars are driven over the standard test course for 20,000 miles, the amount of tread wear (in inches) is recorded, as shown in Table 1. Car Brand 1 Brand 2 Difference(Brand 1 - Brand 2) 1 0.375 0.194 0.181 2 0.238 0.111 0.127 3 0.232 0.265 -0.033 4 0.201 0.184 0.017 5 0.366 0.203 0.163 6 0.206 0.106 0.100 7 0.254 0.311 -0.057 8 0.369 0.242 0.127 9 0.378 0.287 0.091 10 0.349 0.253 0.096 11 0.209 0.235 -0.026 12 0.352 0.188 0.164 Table 1 Based on these data, can the…A consumer products testing group is evaluating two competing brands of tires, Brand 1 and Brand 2. Tread wear can vary considerably depending on the type of car, and the group is trying to eliminate this effect by installing the two brands on the same random sample of 12 cars. In particular, each car has one tire of each brand on its front wheels, with half of the cars chosen at random to have Brand 1 on the left front wheel, and the rest to have Brand 2 there. After all of the cars are driven over the standard test course for 20,000 miles, the amount of tread wear (in inches) is recorded, as shown in the table below. Car 1 2 3 4 5 6 7 8 9 10 11 12 Brand 1 0.35 0.37 0.51 0.59 0.59 0.42 0.59 0.35 0.38 0.40 0.51 0.34 Brand 2 0.37 0.41 0.49 0.48 0.41 0.21 0.53 0.34 0.34 0.48 0.26 0.19 Difference(Brand 1 - Brand 2) −0.02 −0.04…