1. A textile company is interested in knowing if there is a difference in the breaking strength of four different kinds of thread. A test was conducted where five measurements (in ounces) were taken for each kind of thread. Dummy variables were created named threada, threadb, and threadc, which indicated if a strength reading was obtained on thread a, b, or c, respectively. A regression analysis was performed with breaking strength as the dependent variable and threada, threadb, and threadc as independent variables, the results are attached at the end of the sheet. a)  Write the linear model for the regression analysis, give the F statistic and P value for the test of equality of breaking strength means for the four threads, and state your conclusion for the test using alpha = .05.  b) Use the printout from the regression analysis to give estimates of the mean breaking strength for each of the four thread groups.  c) On the regression analysis printout on the row with information about threadb is a t statistic ( t = 0.97, P = 0.3477). Express the null hypothesis that is being tested by this t statistic in terms of the population means i . If we have a single group (such as a control group) that we wish to test against each other group, how can we arrange it so that the regression analysis shows these pairwise tests?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.3: Measures Of Spread
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1. A textile company is interested in knowing if there is a difference in the breaking strength of
four different kinds of thread. A test was conducted where five measurements (in ounces) were
taken for each kind of thread. Dummy variables were created named threada, threadb, and
threadc, which indicated if a strength reading was obtained on thread a, b, or c, respectively. A
regression analysis was performed with breaking strength as the dependent variable and threada,
threadb, and threadc as independent variables, the results are attached at the end of the sheet.

a)  Write the linear model for the regression analysis, give the F statistic and P value
for the test of equality of breaking strength means for the four threads, and state your conclusion
for the test using alpha = .05. 

b) Use the printout from the regression analysis to give estimates of the mean breaking
strength for each of the four thread groups. 

c) On the regression analysis printout on the row with information about threadb is a t
statistic ( t = 0.97, P = 0.3477). Express the null hypothesis that is being tested by this t statistic in
terms of the population means i . If we have a single group (such as a control group) that we
wish to test against each other group, how can we arrange it so that the regression analysis shows
these pairwise tests?

 

 

The REG Procedure
Source
Model
Error
Corrected Total
Model: MODEL1
Dependent Variable: strength
16
DF
Source
Model
Error
Corrected Total
Analysis of Variance
Model 1
Dependent Variable: y
Sum of
Squares
20.88200
20.93600
19 41.81800
Variable DF Estimate
Intercept 1 18.70000
threada 1 -1.92000
threadb 1 0.70000
threadc 1 -1.22000
Parameter Estimates
DF
1
Parameter Standard
14
Mean
Sum of
Squares
36.42785
15.57215
Square F Value Pr > F
6.96067 5.32
0.0098
1.30850
Analysis of Variance
Variable DF Estimate
0.09687
Intercept 1
x1
1
0.76690
Thread data analysis results
Pr > |t|
<.0001
Error t Value
0.51157 36.55
0.72346 -2.65
0.72346 0.97
0.72346 -1.69 0.1111
0.0173
0.3477
15 52.00000
Parameter Estimates
Parameter
Standard
Tutoring data analysis results
Mean
Square F Value Pr > F
36.42785 32.75 <.0001
1.11230
Error t Value Pr > |t|
0.65050
0.15
0.13401
5.72
0.8837
<.0001
Transcribed Image Text:The REG Procedure Source Model Error Corrected Total Model: MODEL1 Dependent Variable: strength 16 DF Source Model Error Corrected Total Analysis of Variance Model 1 Dependent Variable: y Sum of Squares 20.88200 20.93600 19 41.81800 Variable DF Estimate Intercept 1 18.70000 threada 1 -1.92000 threadb 1 0.70000 threadc 1 -1.22000 Parameter Estimates DF 1 Parameter Standard 14 Mean Sum of Squares 36.42785 15.57215 Square F Value Pr > F 6.96067 5.32 0.0098 1.30850 Analysis of Variance Variable DF Estimate 0.09687 Intercept 1 x1 1 0.76690 Thread data analysis results Pr > |t| <.0001 Error t Value 0.51157 36.55 0.72346 -2.65 0.72346 0.97 0.72346 -1.69 0.1111 0.0173 0.3477 15 52.00000 Parameter Estimates Parameter Standard Tutoring data analysis results Mean Square F Value Pr > F 36.42785 32.75 <.0001 1.11230 Error t Value Pr > |t| 0.65050 0.15 0.13401 5.72 0.8837 <.0001
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