1. Calculate the percent composition of sucrose ( C12H22011) %O = 176.00 g/mol x 100 = 51.41% 342.34 g/mol O- 11 x 16.00 = 176.00 g/mol 22.22 g/mol %H = 22.22 g/mol x 100 = 6.49% 342.34 g/mol H- 22 x 1.01 %3D C- 12 x 12.01 g 144.12 g/mol = 342.34 g/mol % C = 144.12 g/mol x 100 = 42.10% 342.34 g/mol %3D Total 100 % Hint: Use the atomic mass of elements in the table below (taken from the Periodic Table of Elements) in solving for Molar Mass and Percentage Composition. Element Atomic Mass Element Atomic Mass Al 26.98 amu CI 35.45 amu C. 12.01 amu Fe 55.84 amu 18:88 8MB 14.01 amu Mg 24.31 amu

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Chapter3: Stoichiometry
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Problem 76E: In 1987 the first substance to act as a superconductor at a temperature above that of liquid...
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B. Percentage Composition
1. Calculate the percent composition of sucrose ( C12H22011)
%O = 176.00 g/mol x 100 = 51.41%
342.34 g/mol
O- 11x 16.00 = 176.00 g/mol
% H = 22.22 g/mol x 100 = 6.49%
342.34 g/mol
H-22 x 1.01
22.22 g/mol
%3D
C- 12 x 12.01 g 144.12 g/mol
= 342.34 g/mol
%C = 144.12 g/mol x 100 = 42.10%
342.34 g/mol
Total
100 %
Hint: Use the atomic mass of elements in the table below (taken from the Periodic
Table of Elements) in solving for Molar Mass and Percentage Composition.
Element
Atomic Mass
Element
Atomic Mass
Al
26.98 amu
CI
35.45 amu
12.01 amu
Fe
55.84 amu
14.01 amu
N.
Mg
24.31 amu
RWB 982L
Transcribed Image Text:B. Percentage Composition 1. Calculate the percent composition of sucrose ( C12H22011) %O = 176.00 g/mol x 100 = 51.41% 342.34 g/mol O- 11x 16.00 = 176.00 g/mol % H = 22.22 g/mol x 100 = 6.49% 342.34 g/mol H-22 x 1.01 22.22 g/mol %3D C- 12 x 12.01 g 144.12 g/mol = 342.34 g/mol %C = 144.12 g/mol x 100 = 42.10% 342.34 g/mol Total 100 % Hint: Use the atomic mass of elements in the table below (taken from the Periodic Table of Elements) in solving for Molar Mass and Percentage Composition. Element Atomic Mass Element Atomic Mass Al 26.98 amu CI 35.45 amu 12.01 amu Fe 55.84 amu 14.01 amu N. Mg 24.31 amu RWB 982L
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