1. Consider that the earth and the atmosphere form a parallel plate of charges. Where the electric field in the region is 301 N/C pointing downward. If a particle whose charge is 0.75 C is placed 1.25 m above the ground, what would be its electric potential energy (in J)? Check the signs carefully. Don't round off. 2. Consider that the earth and the atmosphere form a parallel plate of charges. Where the electric field in the region is 120 N/C pointing downward. If a particle whose charge is -1.75 C is placed 10 m above the ground, what would be its electric potential energy (in J)? Check the signs carefully.

1. Consider that the earth and the atmosphere form a parallel plate of charges. Where the electric field in the region is 301 N/C pointing downward. If a particle whose charge is 0.75 C is placed 1.25 m above the ground, what would be its electric potential energy (in J)? Check the signs carefully. Don't round off. 2. Consider that the earth and the atmosphere form a parallel plate of charges. Where the electric field in the region is 120 N/C pointing downward. If a particle whose charge is -1.75 C is placed 10 m above the ground, what would be its electric potential energy (in J)? Check the signs carefully.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.19P: Given two particles with 2.00-C charges as shown in Figure P25.19 and a particle with charge q =...

See similar textbooks

Similar questions

The naturally occurring charge on the ground on a fine day out in the open country is -1.00nC/m2. (a) What is the electric field relative to ground at a height of 3.00 m? (b) Calculate the electric potential at this height. (C) Sketch electric field and equipotential lines for this scenario.
A CD disk of radius (R = 3.0 cm) is sprayed with a charged paint so that the charge varies continually with radial distance r from the center in the following manner =(6.0C/m)r/R ?. Find the potential at a point 4 cm above the center.
A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm. carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?
Can a particle move in a direction of increasing electric potential, yet have its electric potential energy decrease? Explain
It is shown in Example 24.7 that the potential at a point P a distance a above one end of a uniformly charged rod of length lying along the x axis is V=keQlln(l+a2+l2a) Use this result to derive an expression for the y component of the electric field at P.
Given two particles with 2.00-C charges as shown in Figure P25.19 and a particle with charge q = 1.28 10-18 C at the origin, (a) what is the net force exerted by the two 2.00-C; charges on the charge q? (b) What is the electric field at the origin due to the two 2.00-C particles? (c) What is the electric potential at the origin due to the two 2.00-C particles?
Given two particles with 2.00-C charges as shown in Figure P20.9 and a particle with charge q = 1.28 1018 C at the origin, (a) what is the net force exerted by the two 2.00-C charges on the test charge q? (b) What is the electric field at the origin due to the two 2.00-C particles? (c) What is the electric potential at the origin due to the two 2.00-C particles? Figure P20.9
Oppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600. V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.90 mm from the positive plate?
A point charge of q=50108 C is placed at the center of an uncharged spherical conducting shell of inner radius 6.0 cm and outer radius 9.0 cm. Find the electric potential at (a) r = 4,0cm, (b) r = 8.0 cm, (c) r — 12.0 cm.
Your friend gets really excited by the idea of making a lightning rod or maybe just a sparking toy by connecting two spheres as shown in Figure 7.39, and making R2so small that the electric field is greater than the dielectric strength of air, just from the usual 150 V/m electric field near the surface of the Earth. If R1is 10 cm. how small does R2to be, and does this seem practical? (Hint: recall the calculation for electric field at the surface of a conductor from Gauss's Law.)
Consider two conducting spheres with radii R1 and R2 separated by a distance much greater than cither radius. A total charge Q is shared between the spheres. We wish to show that when the electric potential energy of the system has a minimum value, the potential difference between the spheres is zero. The total charge Q is equal to q1 + q2, where q1 represents the charge on the first sphere and q2 the charge on the second. Because the spheres are very far apart, you can assume the charge of each is uniformly distributed over its surface. (a) Show that the energy associated with a single conducting sphere of radius R and charge q surrounded by a vacuum is UE = keq2/2R. (b) Find the total energy of the system of two spheres in terms of the total charge Q, and the radii and R1 and R2. (c) To minimize the energy, differentiate the result to part (b) with respect to q1 and set the derivative equal to zero. Solve for q1 in terms of Q and the radii. (d) From the result to part (c), find the charge q2. (e) Find the potential of each sphere. (f) What is the potential difference between the spheres?
A simple and common technique for accelerating electrons is shown in Figure 7.46, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving, (a) Calculate the acceleration of the electron if the field strength is 2.50104 N/C . (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole. Figure 7.46 Parallel conducting plates with opposite charges on them create a relatively uniform electric field used to accelerate electrons to the right. Those that go through the hole can be used to make a TV or computer screen glow or to produce X- rays.