1. For the circuit of Figure 1, a load having an impedance of 28+j162 is fed from a voltage source through a line having an impedance of 2+J42. The effective or rms value of the source voltage is 220v. (a) Calculate the load current I, and voltage V (b) Calculate the average and reactive power delivered to the load. (c) Calculate the average and reactive power delivered to the line. (d) Caleulate the average and reactive power supplied by the source. 20 280 220 V (rma) jl6n Source Line Load

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.44P: Two balanced three-phase loads that are connected in parallel are fed by a three-phase line having a...
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1. For the circuit of Figure 1, a load having an impedance of 28+j162 is fed from a voltage
source through a line having an impedance of 2+J42. The effective or rms value of the
source voltage is 220V,
(a) Calculate the load current IL and voltage V
(b) Calculate the average and reactive power delivered to the load.
(c) Calculate the average and reactive power delivered to the line.
(d) Calculate the average and reactive power supplied by the source.
20
j40
280
220/0
V (rms)
j16n
Source -e
Line
Load
Figure 1
Transcribed Image Text:1. For the circuit of Figure 1, a load having an impedance of 28+j162 is fed from a voltage source through a line having an impedance of 2+J42. The effective or rms value of the source voltage is 220V, (a) Calculate the load current IL and voltage V (b) Calculate the average and reactive power delivered to the load. (c) Calculate the average and reactive power delivered to the line. (d) Calculate the average and reactive power supplied by the source. 20 j40 280 220/0 V (rms) j16n Source -e Line Load Figure 1
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